Isolate a single column of values from an array of objects [duplicate]

Question

This is highly similar to a previous question (Create an array from multidimensional array), yet in this case I do not have a multidimensional array. Here is what I have:

Array
(
    [0] => ratings Object
        (
            [id] => 1
            [rating] => 4.4
        )

    [1] => ratings Object
        (
            [id] => 1
            [rating] => 5.0
        )

    [2] => ratings Object
        (
            [id] => 1
            [rating] => 5.0
        )
)

What I'm attempting to do is create a new array that consists of only the "rating" values...

$result_array = array(0 => "4.4",
                      1 => "5.0",
                      2 => "5.0");

The following solution was unsuccessful since $value is an object rather than an array...

$result_array = array();

foreach ($array as $value) {
    $result_array[] = $value[1];
}

What's the correct way to go about it?

As there're 3 elements in $array there will be three iterations in a loop. What do you expect? — u_mulder
– u_mulder, Commented Feb 23, 2014 at 17:17
Amal - still don't know. Was waiting on your answer. You answered the original question so I gave you the check mark for that at least — h.vanoort
– h.vanoort, Commented Feb 23, 2014 at 18:46
Nevermind, very stupid mistake on my part. I was running the print_r within the foreach loop. All is good now. Thanks for the help. — h.vanoort
– h.vanoort, Commented Feb 23, 2014 at 18:59

Amal · Accepted Answer · 2014-02-23 16:24:22Z

1

$result_array[] = $value[1];

With the above line, you're trying to use $value as an array when it's not. It's an object, so treat it as such.

The properties of an object can be accessed using arrow notation (->). The updated code would read:

foreach ($array as $value) {
    $result_array[] = $value->rating;
}

answered Feb 23, 2014 at 16:24

Amal

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