How to assign variables in a string?

Question

I need to assign variables in a string.

 String s = "102, 145, 163, 124";

I want to assign a separate variable like below;

num1 = 102;
num2 = 145;
num3 = 163;
num4 = 124;

I need to do it programatically since the values will change and increase so whatever is in string s is assigned a variable. Thanks

this is java right?: stackoverflow.com/questions/16773599/… — Mazzy
– Mazzy, Commented Feb 25, 2014 at 2:30
If there will ever be more than 4 numbers, you should look into arrays — Blorgbeard
– Blorgbeard, Commented Feb 25, 2014 at 2:32

Cruceo · Accepted Answer · 2014-02-25 02:34:39Z

2

If the values are going to change, you should look into using an ArrayList which will be dynamic and vary with the length of your data.

For instance, you could easily convert all that data to an ArrayList like this:

String string = "102, 145, 163, 124";
ArrayList<Integer> list = new ArrayList<Integer>();
for(String s : string.split(",")) list.add(Integer.parseInt(s.trim()));

Each item would then be accessible by calling it's index like so:

int num0 = list.get(0);
int last = list.get(list.size() - 1);

Storing data in lists is a dynamic approach that's scale-able.

answered Feb 25, 2014 at 2:34

Cruceo

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1 Comment

user3339618 Over a year ago

How can I loop through the items so that they can be written like int[] xAxis = new int[]{102, 145,163,124}; Thanks

Michael Yaworski · Accepted Answer · 2014-02-25 02:38:51Z

1

Because there are a dynamic number of values, you need to use an array (or ArrayList):

String s = "102, 145, 163, 124";

String[] nums = s.split(", ");

// just printing the array
for (int i = 0; i < nums.length; i++) {
    System.out.println(nums[i]);
}

Output of that:

answered Feb 25, 2014 at 2:38

Michael Yaworski

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Comments

GhostDerfel · Accepted Answer · 2014-02-25 02:31:46Z

0

Try to split then parse your strings

String s = "102, 145, 163, 124";
String[] sArray = s.split(",");
List<Integer> integers = new ArrayList<Integer>();
for(String item:sArray){
  integers.add(Integer.parseInt(s.replace(",","")));
}

answered Feb 25, 2014 at 2:31

GhostDerfel

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2 Comments

Cruceo Over a year ago

You might want to also add a trim() to the end of that replace() or else his Strings will throw an IllegalArgumentException or numberFormatException (I can't remember which, but I'm guessing the number one)

GhostDerfel Over a year ago

Can be a trim or change the split to "[0-9]*" but I think the Integer.parseInt(string) can parse numbers with white space in the String (can't test right now)...

a person · Accepted Answer · 2014-02-25 02:31:15Z

0

StringTokenizer tokenizer = new StringTokenizer(s, ", ");
for (int i = 0; i < tokenizer.countTokens(); i++)

answered Feb 25, 2014 at 2:31

a person

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3 Comments

user3339618 Over a year ago

How can I keep the resulting variables in an array? Something like int[] arr = new int[resulting variables in the string]

a person Over a year ago

Define an array int array = new array[tokenizer.countTokens()]. Then array[i] = tokenizer.nextToken() inside loop.

user3339618 Over a year ago

so far this is what I have done, String str = "102, 145, 163, 124"; String[] nums = str.split(","); int[] newArr = new int[nums.length]; for(int i = 0;i < newArr.length;i++) { newArr[i] = Integer.parseInt(nums[i]); int results = newArr[i]; } int[] xAxis = new int[]{results}; // but this code is not working. I need to keep the results in the int[] xAxis.

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