JavaScript If Else with Return

Question

Still doing the Codecademy training for JavaScript and I've hit a road block.

Here's the code:

var isEven = function(number) {
if (isEven % 2 === 0) {
  return true;
} else {
  return false;
}
};

isEven(2);

So I'm referencing the variable "isEven." Then, I'm telling it to check the number and cross-check it with the modulo to check the remainder against 2 to find out if it's even. If it is, for example, 2 like in the example it should return a remainder of zero, therefore the if is true and it returns true. But it returns false every time. There's no warning messages in the code but when I hit save and it checks it it gives me this message:

"Oops, try again. Looks like your function returns false when number = 2. Check whether your code inside the if/else statement correctly returns true if the number it receives is even."

You are trying to do a modulo on a function reference here – which of course makes no sense at all. The parameter you are passing into the function is called number … — C3roe
– C3roe, Commented Feb 27, 2014 at 21:03
Take a second and look at what isEven really is defined to be. — Derek 朕會功夫
– Derek 朕會功夫, Commented Feb 27, 2014 at 21:05
It should be function isEven(number){ return number % 2 === 0; } — Derek 朕會功夫
– Derek 朕會功夫, Commented Feb 27, 2014 at 21:05
@Derek朕會功夫 Yeah, every programmer would do that, but that's not what Codecademy is about (at least not the basic JavaScript courses). — Tobias
– Tobias, Commented Feb 27, 2014 at 21:12

NBR · Accepted Answer · 2021-02-10 18:32:01Z

6

I think you had the wrong variable name:

var isEven = function(number) {
    if (number % 2 === 0) {
        return true;
    } 
    return false;
    
};

isEven(2);

edited Feb 10, 2021 at 18:32

NBR

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answered Feb 27, 2014 at 21:03

Popo

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Comments

GetSwifty · Accepted Answer · 2016-07-01 17:44:04Z

5

you could also do:

var isEven = function(number) {
    return number % 2 === 0
};

answered Jul 1, 2016 at 17:44

GetSwifty

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Comments

Igor Šćekić · Accepted Answer · 2014-02-27 21:03:55Z

0

Your function and variable have the same name. Name the function or the variable differently and it will work.

answered Feb 27, 2014 at 21:03

Igor Šćekić

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Comments

andrey.rtv · Accepted Answer · 2014-02-27 21:06:24Z

0

You need change varible isEven to number, like:

var isEven = function(number) {
if (number % 2 === 0) {
return true;
} else {
return false;
}
};

isEven(2);

answered Feb 27, 2014 at 21:06

andrey.rtv

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