PHP json_decode Not Working

Question

Alright, so, I have a game that uploads data in the form of JSON to my site. The JSON resembles this:

{
  "PlayerList":[
    {
        "PlayerKills":0,
        "Username":"Player1",
        "TimePlayed":0,
        "Deaths":0
    },
    {
        "PlayerKills":0,
        "Username":"Player1",
        "TimePlayed":0,
        "Deaths":0
    }
  ]
}

After confirming that the JSON is indeed correct, and without errors, I began speculating that the problem lie in the PHP. The code I use to get the JSON is:

$decodedJSON =  json_decode($entityBody, true, 4);              
var_dump($decodedJSON);

With $entitybody being the JSON as a string.

The var_dump here returns NULL, and since I'm stuck using PHP 5.2, I cannot determine what the problem is using json_last_error.

So if anyone can provide me some info as to where the problem lies, it would be much appreciated.

me too got this error when my json data format was wrong(make sure json format is correct with the following link..... even if it seems correct), and i corrected using JSONLint an json validator — Jose Kj
– Jose Kj, Commented Sep 4, 2017 at 8:11
You most definitely should not be using PHP 5.2. It's been EOL'd for years and if you're running it on the public internet then you're wide open to a whole host of security vulnerabilities. — GordonM
– GordonM, Commented Sep 4, 2017 at 8:17
Check if your data is UTF-8 with a Byte Order Mark. I removed my BOM and my problems went away — NoLifeKing
– NoLifeKing, Commented Nov 27, 2017 at 14:20

Akshay Kalose · Accepted Answer · 2014-03-03 23:16:02Z

7

Try this:

$entityBody = stripslashes($entityBody);
// this will remove all backslashes which might be the cause of returning NULL

$decodedJSON = json_decode($entityBody, true);
// leave out the depth unless you really need it to be 4.

var_dump($decodedJSON);

Documentation:

stripslashes - http://php.net/manual/en/function.stripslashes.php

json_decode - http://php.net/json_decode

answered Mar 3, 2014 at 23:16

Akshay Kalose

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Niet the Dark Absol · Accepted Answer · 2014-03-03 22:30:55Z

4

Don't set the depth parameter. Just json_decode($entityBody,true); should work.

answered Mar 3, 2014 at 22:30

Niet the Dark Absol

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Comments

Foo L · Accepted Answer · 2014-03-03 23:05:00Z

1

In PHP 5.2 json_decode requires 2 parameters not 3. I checked it on PHP 5.2.17 and it shows:

Warning: json_decode() expects at most 2 parameters, 3 given.

If you omit third parameter you will get what you want :)

edited Mar 3, 2014 at 23:05

Foo L

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answered Mar 3, 2014 at 22:42

Lukas Pawlik

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