I have a json store in jsonFile
{
"key1": "aaaa bbbbb",
"key2": "cccc ddddd"
}
I have code in mycode.sh:
#!/bin/bash
value=($(jq -r '.key1' jsonFile))
echo "$value"
After I run ./mycode.sh the result is aaaa
but if I just run jq -r '.key1' jsonFile the result is aaaa bbbbb
Could anyone help me?
With that line of code
value=($(jq -r '.key1' jsonFile))
you are assigning both values to an array. Note the outer parantheses () around the command.
Thus you can access the values individually or echo the content of the entire array.
$ echo "${value[@]}"
aaaa bbbb
$ echo "${value[0]}"
aaaa
$ echo "${value[1]}"
bbbb
Since you echoed $value without specifying which value you want to get you only get the first value of the array.
echo '{ "foo": "foovalue1 foovalue2", "bar": "barvalue" }' output: "foovalue1 foovalue2" "barvalue" I want to save it to bash array as two (not three!) elements, like: array=($(echo '{ "foo": "foovalue1 foovalue2", "bar": "barvalue" }' | jq -r '.foo, .bar'))local result=$(<your_json_response>)
local aws_access_key=$(jq -r '.Credentials.AccessKeyId' <<< ${result})
local aws_secret_key=$(jq -r '.Credentials.SecretAccessKey' <<< ${result})
local session_token=$(jq -r '.Credentials.SessionToken' <<< ${result})
Above code is another way to get the values from json response.
