How to add to an array in a loop

Question

I’m trying to add to an array in a loop but only the first element in the loop is added.

The array

array (size=7)
  0 => 
    array (size=2)
      'id' => int 1
      'name' => string 'john' (length=11)
  1 => 
    array (size=2)
      'id' => int 2
      'name' => string 'adam' (length=13)
  2 => 
    array (size=2)
      'id' => int 3
      'name' => string 'mary' (length=11)

My loop

foreach ($loops as $key => $loop) {
    $idArray['id'] =  $loop['id'];
}
var_dump($idArray); die();

Did I do anything wrong?

That is because you are overwritting the key. Also, an array can't have identical keys. — Shankar Narayana Damodaran
– Shankar Narayana Damodaran, Commented Mar 30, 2014 at 15:23
you are overwriting the same variable over and over and over again — Chris
– Chris, Commented Mar 30, 2014 at 15:23

Tobias Golbs · Accepted Answer · 2014-03-30 15:22:56Z

2

You overwrite your old value by assigning the new value to the array. An array can't have identical keys.

Try this:

foreach ($loops as $key => $loop)
{             
    $idArray['id'][] =  $loop['id'];
}
var_dump($idArray); die();

So you add items to an array inside your array.

answered Mar 30, 2014 at 15:22

Tobias Golbs

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robbmj · Accepted Answer · 2014-03-30 15:27:47Z

0

If you want the ordinal values of the $idarray to be the primary key values of what you are iterating over you can do this.

$loops = array(array('id' => 1, 'name' => 'john'), /* ... */);

foreach ($loops as $key => $loop)
{             
    $idArray[$loop['id']] =  $loop;
}
var_dump($idArray); die();

var_dump will reveal this structure

array (size=7)
  1 => 
    array (size=2)
      'id' => int 1
      'name' => string 'john' (length=4)
  2 => 
    array (size=2)
      'id' => int 2
      'name' => string 'adam' (length=4)
  3 => 
    array (size=2)
      'id' => int 3
      'name' => string 'mary' (length=4)

answered Mar 30, 2014 at 15:27

robbmj

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