Parsing JSONArray in Android

Question

I am new to json parsing and am caught up big time. I have to parse the following:-

[
  {
    "firstname": abc,
    "lastname": xyp,
    "designation" : executive,
    "user": {
      "username": "xypabc",
      "userid": 4003,
      },
  },

  {
    "firstname": pqr,
    "lastname": vbn,
    "designation" : security,
    "user": {
      "username": "vbnpqr",
      "userid": 11231,
      },
  },    


  {
    "firstname": ghk,
    "lastname": lkj,
    "designation" : manager,
    "user": {
      "username": "lkjghk",
      "userid": 774,
      },
  }
]

I need to fetch the "login" and "userid" from above. Below is the code which I wrote :-

try {
    JSONArray jsonObj = new JSONArray(response);
    for(int i=0 ; i<jsonObj.length(); i++)
    {                                       
        JSONObject json_Data = jsonObj.getJSONObject(i);
        String userName = json_Data.getString("username");
        String userId = json_Data.getString("userid");
        Log.d("Factors","UserName :- "+userName+" ID :- "+userId);
    }
    }catch (JSONException e) {
        Log.d("Failure","Dude I have failed");
    }.

The problem is that my code ends up with exception. Please help !!!

your forgot parsing "user": { under which you ahve username and id — Raghunandan
– Raghunandan, Commented Apr 8, 2014 at 11:24

Nambi · Accepted Answer · 2014-04-08 11:25:28Z

1

username and userid is within the user JSONObject parse the user JSONObject and then get the string of the username and userid.

DO like this to get the username and userid

for(int i=0 ; i<jsonObj.length(); i++)
    {                                       
        JSONObject json_Data = jsonObj.getJSONObject(i);
        String userName = json_Data.getJSONObject("user").getString("username");
        String userId = json_Data.getJSONObject("user").getString("userid");
        Log.d("Factors","UserName :- "+userName+" ID :- "+userId);
    }

answered Apr 8, 2014 at 11:25

Nambi

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2 Comments

saugatchetry Over a year ago

Thanks @Nambi Narayanan .. works wonderfully !!! ... but I regret I cant "vote-up" ur answer as i dont have enough reputation :( . Neways thanks a ton

Joris Over a year ago

Consider looking into the Gson parser as well, it is quite amazing.

Thanh Le · Accepted Answer · 2014-04-08 11:25:20Z

0

Parsing: "user"

   try {
        JSONArray jsonObj = new JSONArray(response);
        for(int i=0 ; i<jsonObj.length(); i++)
        {                                       
            JSONObject json_Data = jsonObj.getJSONObject(i);
            JSONObject user = json_Data.getJSONObject("user");
            String userName = user.getString("username");
            String userId = user.getString("userid");
            Log.d("Factors","UserName :- "+userName+" ID :- "+userId);
        }
        }catch (JSONException e) {
            Log.d("Failure","Dude I have failed");
        }

answered Apr 8, 2014 at 11:25

Thanh Le

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Comments

Trupti · Accepted Answer · 2014-04-08 11:35:01Z

0

JSONArray jresult = new JSONArray(response);

jresult = json.getJSONArray("user");
for (int i = 0; i < jresult .length(); i++) 
{
JSONObject obj  = jresult .getJSONObject(i);
String username=obj.getString("username");
int userid=obj.getInt("userid");
}

answered Apr 8, 2014 at 11:35

Trupti

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Comments

Zar E Ahmer · Accepted Answer · 2014-04-08 11:41:55Z

if(result != null)
            {
                try
                {
                    JSONObject jobj = result.getJSONObject("result");

                    String status = jobj.getString("status");

                    if(status.equals("true"))
                    {
                        JSONArray array = jobj.getJSONArray("user");

                        for(int x = 0; x < array.length(); x++)
                        {
                            HashMap<String, String> map = new HashMap<String, String>();

                            map.put("username", array.getJSONObject(x).getString("username"));

                            map.put("userid", array.getJSONObject(x).getString("userid"));



                            list.add(map);
                        }

                        CalendarAdapter adapter = new CalendarAdapter(Calendar.this, list);

                        list_of_calendar.setAdapter(adapter);
                    }
                }
                catch (Exception e) 
                {
                    e.printStackTrace();
                }

droidster.me · Accepted Answer · 2014-04-08 11:58:08Z

Try this code : :)

  JSONArray jsonObj = new JSONArray(response);
                for(int i=0 ; i<jsonObj.length(); i++)
                {                                       
                    JSONObject json_Data = jsonObj.getJSONObject(i);
                    String firstname = json_Data.getString("firstname");
                    String lastname = json_Data.getString("lastname");
                    String designation = json_Data.getString("designation");

                    JSONArray jsons1 = json_Data.getJSONArray("user");
                    for (int j = 0; j < jsons1.length(); j++) {

                        JSONObject jsonss = jsons1.getJSONObject(j);
                         String username = jsonss.getString("username");
                            String userid = jsonss.getString("userid");
                    }

                }
                }catch (JSONException e) {
                    Log.d("Failure","Dude I have failed");
                }

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