PHP: Parsing XML - output with style

Question

I have done this little script.

<?php 
$url = "http://resurse.fibula.ro/parteneri/xmlhotels.php?location=belek&myid=travelplaza";
$xml = simplexml_load_file($url);
foreach($xml->hotel as $hotel)
{
echo "<p>";
echo "<strong>Title:</strong> ".$hotel->description."<br/>";
echo "</p>";

}

In the link above I've some images that I want to put under the description of each hotel. I have tried to get the images like i did with the description, like so:

echo .$hotel->images"<br/>";

But I get an error

" Parse error: syntax error, unexpected '.' in C:\Program Files (x86)\EasyPHP-DevServer-14.1VC11\binaries\home\2.php on line 9"

Any help would be very much appreciated. An example or o resource where to read about it. For dummies I mean.

Thank you.

hek2mgl · Accepted Answer · 2014-04-09 08:34:34Z

0

line 9 should look like this:

echo $hotel->images . "<br/>";

Having the . between the variable and the <br/> string. I encourage you to learn the basic PHP syntax.

edited Apr 9, 2014 at 8:34

answered Apr 9, 2014 at 8:27

hek2mgl

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2 Comments

Valy Over a year ago

added this linne but now i get this result : Parse error: syntax error, unexpected '"<br/>"' (T_CONSTANT_ENCAPSED_STRING), expecting ',' or ';' in C:\Program Files (x86)\EasyPHP-DevServer-14.1VC11\binaries\home\2.php on line 9

Valy Over a year ago

Inseted the above echo ... but... it gives me no error, but there are no images showing. If you acces the link directly you can see the images url.

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