PHP Counting inside an Array

Question

I want to create a list where if its already in the array to add to the value +1.

Current Output

[1] => Array
    (
        [source] => 397
        [value] => 1
    )

[2] => Array
    (
        [source] => 397
        [value] => 1
    )

[3] => Array
    (
        [source] => 1314
        [value] => 1
    )

What I want to Achieve

[1] => Array
    (
        [source] => 397
        [value] => 2
    )

[2] => Array
    (
        [source] => 1314
        [value] => 1
    )

My current dulled down PHP

        foreach ($submissions as $timefix) {

              //Start countng
              $data = array(
                    'source' => $timefix['parent']['id'],
                    'value' => '1'
              );

              $dataJson[] = $data;

    }

            print_r($dataJson);

h2ooooooo · Accepted Answer · 2014-04-14 10:51:24Z

2

Simply use an associated array:

$dataJson = array();

foreach ($submissions as $timefix) {
    $id = $timefix['parent']['id'];

    if (!isset($dataJson[$id])) {
        $dataJson[$id] = array('source' => $id, 'value' => 1);
    } else {
        $dataJson[$id]['value']++;
    }
}

$dataJson = array_values($dataJson); // reset the keys - you don't nessesarily need this

answered Apr 14, 2014 at 10:51

h2ooooooo

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Comments

mingos · Accepted Answer · 2014-04-14 10:52:46Z

1

This is not exactly your desired output, as the array keys are not preserved, but if it suits you, you could use the item ID as the array key. This would simplify your code to the point of not needing to loop through the already available results:

foreach ($submissions as $timefix) {
    $id = $timefix['parent']['id'];
    if (array_key_exists($id, $dataJson)) {
        $dataJson[$id]["value"]++;
    } else {
        $dataJson[$id] = [
            "source" => $id,
            "value" => 1
        ];
    }
}
print_r($dataJson);

answered Apr 14, 2014 at 10:52

mingos

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Comments

dkasipovic · Accepted Answer · 2014-04-14 10:52:49Z

0

You should simplify this for yourself. Something like:

<?
  $res = Array();
  foreach ($original as $item) {
    if (!isset($res[$item['source']])) $res[$item['source']] = $item['value'];
    else $res[$item['source']] += $item['value'];
  }
?>

After this, you will have array $res which will be something like:

Array(
  [397] => 2,
  [1314] => 1
)

Then, if you really need the format specified, you can use something like:

<?
  $final = Array();
  foreach ($res as $source=>$value) $final[] = Array(
    'source' => $source,
    'value' => $value
  );
?>

answered Apr 14, 2014 at 10:52

dkasipovic

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Comments

dezlov · Accepted Answer · 2014-04-14 10:57:58Z

0

This code will do the counting and produce a $new array as described in your example.

$data = array(
    array('source' => 397, 'value' => 1),
    array('source' => 397, 'value' => 1),
    array('source' => 1314, 'value' => 1),
);

$new = array();
foreach ($data as $item)
{
    $source = $item['source'];
    if (isset($new[$source]))
        $new[$source]['value'] += $item['value'];
    else
        $new[$source] = $item;
}
$new = array_values($new);

answered Apr 14, 2014 at 10:57

dezlov

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Comments

mah · Accepted Answer · 2014-04-14 11:12:06Z

0

PHP has a function called array_count_values for that. May be you can use it

Example:

<?php
$array = array(1, "hello", 1, "world", "hello");
print_r(array_count_values($array));
?>

Output:

Array
(
    [1] => 2
    [hello] => 2
    [world] => 1
)

edited Apr 14, 2014 at 11:12

mah

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answered Apr 14, 2014 at 10:47

opensource-developer

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