I want to convert an number (integer) to a hex string
2 (0x02) to "\x02"
or
62 (0x0062) to "\x62"
How can I do that correctly?
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@Chuck nope that does not cut it^^DarkLeafyGreen– DarkLeafyGreen2014-04-17 00:09:07 +00:00Commented Apr 17, 2014 at 0:09
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how does that not cut it?Keith Nicholas– Keith Nicholas2014-04-17 00:14:44 +00:00Commented Apr 17, 2014 at 0:14
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1are you seriously having problems add \x to the hex number?Keith Nicholas– Keith Nicholas2014-04-17 00:15:04 +00:00Commented Apr 17, 2014 at 0:15
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@KeithNicholas No, but I have a problem understanding it, there seems to be a difference between \x2 and \x02. And how can I now that 0x0062 is \x62 as string.DarkLeafyGreen– DarkLeafyGreen2014-04-17 00:19:02 +00:00Commented Apr 17, 2014 at 0:19
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1Leading zeroes in hexadecimal don't make any numeric difference. 9 == 09 == 009 == 0009… ad infinitum. I think whatever service you're giving the string to is just a little bit eccentric.Chuck– Chuck2014-04-17 00:37:05 +00:00Commented Apr 17, 2014 at 0:37
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3 Answers
You can use the to string method:
a = 64;
a.toString(16); // prints "40" which is the hex value
a.toString(8); // prints "100" which is the octal value
a.toString(2); // prints "1000000" which is the binary value
8 Comments
DarkLeafyGreen
It has to be in "\x62" format.
volter9
a = 64; a = '\x' + a.toString(16);
Ibu
you can easily concatenate that.
Sharcoux
Doesn't work with 2 as the OP explicitly required the function to return \x02 and not \x2
Mqx
@Ibu no you can not... stackoverflow.com/questions/23122373/…
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Well, it's seems that you want just to concatenate the integer with \x.
If so just to like that:
var number = 62;
var hexStr = '\x' + number.toString(16);
But you have something strange about explaining.
Note: that 62 is not the same as 0x62, 0x62 would be 98.
4 Comments
DarkLeafyGreen
What if number = 2? hexStr would be \x2, but should be \x02
volter9
But what the difference? The value still would be 2. If you need so I'll give you the answer, but there's no difference.
DarkLeafyGreen
If I would do this in python I would get "invalid \x escape' while \x02 would be excepted, so there seems to be a difference...
volter9
You're asking about JS, ok never mind. Just add
var hexStr = '\x0' + number.toString(16);var converted = "\x" + number.toString(16)
