php server side code to upload image

Question

     $path1='./upload/'.$userid.'/';


     if(!$path1.$category_name.'_'.$i.'_product_image1.jpg')
     {
        $file1 = fopen($path1.$category_name.'_'.$i.'_product_image1.jpg', 'wb');
        $file2 = fopen($path1.$category_name.'_'.$i.'_product_image2.jpg', 'wb');
        $file3 = fopen($path1.$category_name.'_'.$i.'_product_image3.jpg', 'wb');

        fwrite($file1, $binary1);
        fwrite($file2, $binary2);
        fwrite($file3, $binary3);

        $path = $category_name.'_'.$i;
 }
     else {"already exists";}

     $Gimage1 = mysql_real_escape_string(base_url($path1.$path.'_product_image1.jpg'));
     $Gimage2 = mysql_real_escape_string(base_url($path1.$path.'_product_image2.jpg'));
     $Gimage3 = mysql_real_escape_string(base_url($path1.$path.'_product_image3.jpg'));

     fclose($file1);
     fclose($file2);
     fclose($file3);

why is the if condition not checking whether image in that path already not exists... it simply enters into if condition so please help.

MSadura · Accepted Answer · 2014-04-17 07:05:15Z

2

It happens because you dont check if file exists...

if(!file_exists($path1.$category_name.'_'.$i.'_product_image1.jpg'));

Your current code checks if condition is not false, which is not (it contains not empty string with path), but it have nothing to do with the fact that file exists or not.

File exists manual

edited Apr 17, 2014 at 7:05

answered Apr 17, 2014 at 6:24

MSadura

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