PHP Search Array in Array and add value

Question

i have the following array:

Array $a
(
[1] => Array
    (
        [id] => 1
        [name] => Shoes
    )

[2] => Array
    (
        [id] => 2
        [name] => Shirts
    )

[3] => Array
    (
        [id] => 3
        [name] => Jeans
    )
)

And i've got this array:

Array $b
(
[0] => [1]
[1] => [5]
[2] => [6]
)

Now i want to find out, if one value of $b matches the [id] in $a. If so i want to add a new value ['hasID'] => true inside $a.

The solutions should look like this:

Array $a
(
[1] => Array
    (
        [id] => 1
        [name] => Shoes
        [hasID] => true
    )

[2] => Array
    (
        [id] => 2
        [name] => Shirts
        [hasID] => false
    )

[3] => Array
    (
        [id] => 3
        [name] => Jeans
        [hasID] => false
    )
)

My try was this:

    foreach($a as $ak => $av) {
        foreach($b as $bk => $bv) {     
            if($bv == $ak['id']) {
                $a[$ak]['hasID'] == true;   
            } else {
                $a[$ak]['hasID'] == false;
            }
        }
    }

That doesn't work so. I've tried hours. Any ideas?

Thank you very much!

Regards

Community · Accepted Answer · 2020-06-20 09:12:55Z

2

Loop through the first array and check if the value of $arr['id'] exists under the second array of ids. If found, add a flag as true or 1 , else false or 0.

foreach($arr1 as $k=>&$arr) //<--- As you can see I have  added & (Reason below)
{
   in_array($arr['id'],$arr2) ? $arr['hasID']= true : $arr['hasID']=false;
}

print_r($arr1);

Working Demo

Reason : To modify the array directly , you use the reference operator.

One-liner `array_walk()`

array_walk($arr1,function (&$v,$k) use($arr2){ in_array($v['id'],$arr2)? $v['hasID']=true : $v['hasID']=false; });

edited Jun 20, 2020 at 9:12

CommunityBot

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answered Apr 17, 2014 at 13:11

Shankar Narayana Damodaran

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4 Comments

MackieeE Over a year ago

You've implemented a few things there that a newcomer might not understand; references & why == won't work over =.

Shankar Narayana Damodaran Over a year ago

@MackieeE, I hope I explained the reference thing. Thanks for the headsup.

Pascal Cloverfield Over a year ago

Wow! This works and is short and sexy. And i've learnt something new with the reference operator. Thank you very much! :)

Shankar Narayana Damodaran Over a year ago

@PascalCloverfield, Reduced the code even more down and added an array_walk version. Happy coding :)

ôkio · Accepted Answer · 2014-04-17 13:14:36Z

0

Your try is not working because you use double == instead of simple = for value attribution. This should works :

foreach($a as $ak => $av) {
    foreach($b as $bk => $bv) {     
        if($bv == $ak['id']) {
            $a[$ak]['hasID'] = true;   
        } else {
            $a[$ak]['hasID'] = false;
        }
    }
}

However the solution with in_array is a better choice for performance reason.

answered Apr 17, 2014 at 13:14

ôkio

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Comments

Neeraj · Accepted Answer · 2014-04-17 13:15:27Z

0

<?php 
$arr1 = array('1'=>'shoes','2'=>'shirts','3'=>'jeans');
$arr2 = array('0'=>'1','1'=>'5','2'=>'6');

$i = 0;
foreach($arr1 as $k=>$val)
{
    if($arr2[$i] == 1)
    {
        $ARR[$k][] = $k;
        $ARR[$k][] = $val;
        $ARR[$k][] = 'true';
    }
    else
    {
        $ARR[$k][] = $k;
        $ARR[$k][] = $val;
        $ARR[$k][] = 'false';
    }
    $i++;
}
echo "<pre>";
    print_r($ARR);
echo "</pre>";
?>

answered Apr 17, 2014 at 13:15

Neeraj

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One-liner `array_walk()`

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One-liner array_walk()

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