How can I limit the user input to only integers in Python

The best way would be to use a helper function which can accept a variable type along with the message to take input.

def _input(message, input_type=str):
    while True:
      try:
        return input_type (input(message))
    except:pass

if __name__ == '__main__':
    _input("Only accepting integer : ", int)
    _input("Only accepting float : ", float)
    _input("Accepting anything as string : ")

So when you want an integer , you can pass it that i only want integer, just in case you can accept floating number you pass the float as a parameter. It will make your code really slim so if you have to take input 10 times , you don't want to write try catch blocks ten times.

def func():
    choice = "Wrong"
    
    while choice.isdigit()==False :
        choice = input("Enter a number: ")
        
        if choice.isdigit()==False:
            print("Wrongly entered: ")
        else:
            return int(choice)

One solution amongst others : use the type function or isinstance function to check if you have an ̀int or a float or some other type

>>> type(1)
<type 'int'>

>>> type(1.5)
<type 'float'>

>>> isinstance(1.5, int)
False

>>> isinstance(1.5, (int, float))
True   

I would catch first the ValueError (not integer) exception and check if the answer is acceptable (within 1, 2, 3) or raise another ValueError exception

def survey():
    print('1) Blue')
    print('2) Red')
    print('3) Yellow')

    ans = 0
    while not ans:
        try:
            ans = int(input('Out of these options\(1, 2, 3), which is your favourite?'))
            if ans not in (1, 2, 3):
                raise ValueError
        except ValueError:
            ans = 0
            print("That's not an option!")

    if ans == 1:
        print('Nice!')
    elif ans == 2:
        print('Cool')
    elif ans == 3:
        print('Awesome!')
    return None

I made a module for cases like this called restricted_input which checks the input in real time. Here, since you only need inputs from 1-3, this would do

from restricted_input import r_input
num = int(r_input("Out of these options\(1,2,3), which is your favourite? ", input_type="nothing", allow="123", maxlength=1))

It uses msvcrt.getch/termios to get non-blocking input, so it checks it in real time and allows only the specified characters.
Note: This will not work in IDLEs like Spyder, Jupyter etc.

# force user to input a number between 0 - 4 (1,2,3)
def input_int():
    num = ""
    i = 0
    while type(num) is not int:
        # user have 3 chance to try:
        if i > 2:
            print("try later")
            exit(1)
        i += 1
        # input int
        try:
            num = int(input("{} form {} try! please insert int num: ".format(i, 3)))
            # checking number for being upper than zero and lower than 3 (1, 2, 3)
            if 0 > num or num > 3:
                num = ""
                print("That's an invalid answer")
                continue
        # if the input is not a int, user have to input another value
        except ValueError:
            print("That's an invalid answer")
            continue
    # if input for num was valid, return num
    return num

from msvcrt import getch

def survey():
    comment = ['Nice!', 'Cool', 'Awesome!']

    while True:        
        print('\n1) Blue', '2) Red', '3) Yellow', sep='\n', end='')
        print('\nOut of these options\(1,2,3), which is your favourite? ', end='')

        try:
            answer = getch().decode()   # input of 1 character
        except UnicodeDecodeError:      # error from del, home, pg up, etc., keys
            continue

        if answer in '123':    
            print(answer, end=' ')  # print the entered char 
            print(comment[int(answer)-1])
            break             
        else:
            print('\nThat\'s not an option! Please, try again...')

survey()

Running on Windows with msvcrt standard lib. If you want to allow a escape way without answering by pressing [ENTER], insert next to the if clause:

elif answer == '\r': break

You can use a module named PyInputPlus.

Installation:

pip install PyInputPlus

You can use this as

def Survey():
    print('1) Blue')
    print('2) Red')
    print('3) Yellow')
    question = int(input('Out of these options\(1,2,3), which is your favourite?'))
    if question == 1:
        print('Nice!')
    elif question == 2:
        print('Cool')
    elif question == 3:
        print('Awesome!')
    else:
        print('That\'s not an option!')