Java & Regular expression

Question

Need help with parsing line where keywords included in brackets [].

I tried but have wrong result:

public class App {
    public static void main(String[] args) {

        Matcher mtr = Pattern.compile("(\\w+-\\w+|\\w+)+").matcher("[foo-bar] [baz][qux]");

        if (mtr.find()) for (int i = 0; i < mtr.groupCount(); i++) {
            System.out.println(mtr.group(i));
        }
    }
}

Result(wrong):

foo-bar

Me need:

foo-bar
baz
qux

What should be regex that parse string as on last example ?

you need to call find() in a loop until it stops finding. the groups are the groups for a single match, not all the matches. — jtahlborn
– jtahlborn, Commented May 13, 2014 at 18:40

Braj · Accepted Answer · 2014-05-13 18:41:04Z

1

Simply try using String#split() method.

String str = "[foo-bar] [baz][qux]";
String[] array = str.substring(1, str.length() - 1).split("\\]\\s*\\[");

answered May 13, 2014 at 18:41

Braj

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2 Comments

quant Over a year ago

This will leave "[" and "]" in array[0] and array[array.length - 1] which is not wanted. "[foo-bar" instead of foo-bar.

Braj Over a year ago

I don't think so. That's why substring is used.

Evgeniy Dorofeev · Accepted Answer · 2014-05-13 18:41:25Z

1

try this

    Matcher mtr = Pattern.compile("[\\w-]+").matcher("[foo-bar] [baz][qux]");
    while(mtr.find()) {
        System.out.println(mtr.group());
    }

answered May 13, 2014 at 18:41

Evgeniy Dorofeev

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Comments

anubhava · Accepted Answer · 2014-05-13 18:42:03Z

1

Instead of if (mtr.find()):

while (mtr.find())
   for (int i = 0; i < mtr.groupCount(); i++) {
      System.out.println(mtr.group(i));
   }

i.e. you need to call matcher#find() inside a loop to have global matched returned.

answered May 13, 2014 at 18:42

anubhava

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Comments

Sam I am says Reinstate Monica · Accepted Answer · 2014-05-13 18:43:49Z

1

try this retular expression

\[[^\[\]]*\]

http://rubular.com/r/heMGeTMjuB

alternatively, this one is similar, and will parse things such as "[foo[bar]" as foo[bar

\[(.*?)\]

http://rubular.com/r/IzPI0RcLmS

answered May 13, 2014 at 18:43

Sam I am says Reinstate Monica

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Comments

arshajii · Accepted Answer · 2014-05-13 18:49:31Z

1

As long as your brackets can't be nested, you can try the regex

\[([^\]]*)\]

and extract the first capturing group.

That is:

Matcher mtr = Pattern.compile("\\[([^\\]]*)\\]").matcher("[foo-bar] [baz][qux]");

while (mtr.find())
    System.out.println(mtr.group(1));

foo-bar
baz
qux

edited May 13, 2014 at 18:49

answered May 13, 2014 at 18:43

arshajii

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