Accessing nested structures in python

Question

I have a structure sw_list formatted as given below

 {'ports': [{'hw_addr': 'ee:b1:ab:b1:0e:a0', 'name': 's1-eth1', 'port_no': '00000001', 'dpid': '0000000000000201'}, 
            {'hw_addr': 'f6:83:4d:e4:41:7d', 'name': 's1-eth2', 'port_no': '00000002', 'dpid': '0000000000000201'}
                       ], 'dpid': '0000000000000201'}


for index,switch in enumerate(sw_list):
              dpid_str = dpid_to_str(switch.dp.id)

The above loop will print dpid_str which is '0000000000000201' ath the end of the structure. Now I want to access the contents of ports structure such as

Port 0: hw_addr,name,port_no etc

How do I do that?

So sw_list is not actually a list but rather a dict? Also, what is the dangling ) at the end supposed to close? — dg99
– dg99, Commented Jun 5, 2014 at 23:24

Padraic Cunningham · Accepted Answer · 2014-06-05 23:44:55Z

1

d={'ports': [{'hw_addr': 'ee:b1:ab:b1:0e:a0', 'name': 's1-eth1', 'port_no': '00000001', 'dpid': '0000000000000201'},
            {'hw_addr': 'f6:83:4d:e4:41:7d', 'name': 's1-eth2', 'port_no': '00000002', 'dpid': '0000000000000201'}
                       ], 'dpid': '0000000000000201'}

for i in d["ports"][0]:
    print "{} : {}".format(i,d["ports"][0][i])
hw_addr : ee:b1:ab:b1:0e:a0
name : s1-eth1
port_no: 00000001
dpid : 0000000000000201

answered Jun 5, 2014 at 23:44

Padraic Cunningham

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