How To Upload File with Django Rest APi

Question

can someone help me how to upload file with POST method in django rest api, for example when I launch

curl -X POST 127.0.0.1:8000/api/v1/assets/ -d '{"name" = "my image   ","source"="/root/images/my_image2.jpg"}' -H "Content-Type: application/json"

I want to upload my_image2.jpg

serializers.py:

from django.forms import widgets
from rest_framework import serializers
from .models import Asset

class AssetSerializer(serializers.ModelSerializer):
    class Meta:
        model = Asset

views.py:

from .serializers import AssetSerializer
from django.http import Http404
from rest_framework.views import APIView
from rest_framework.response import Response
from rest_framework import status

from rest_framework import status
from rest_framework.decorators import api_view


class AssetAdd(APIView):


    def post(self, request, format=None):
        serializer = AssetSerializer(data=request.DATA)
        print serializer.data

        if serializer.is_valid():

            serializer.save()
            return Response(serializer.data, status=status.HTTP_201_CREATED)

        return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)

models.py

class Asset(models.Model):

    key = models.CharField(max_length=8, unique=True, editable=False)
    name = models.CharField(_('name'), max_length=200)
    source = models.FileField(_('file'), upload_to=upload_to, storage=default_storage)

    ext = models.CharField(max_length=15, editable=False)
    type = models.PositiveIntegerField(choices=ASSET_TYPE, max_length=15, editable=False)
    size = models.PositiveIntegerField(max_length=32, default=0, editable=False)

    _file_meta = models.TextField(editable=False, null=True, blank=True)

    public = models.BooleanField(default=False)
    position = models.PositiveIntegerField(default=1)

    object_id = models.PositiveIntegerField(default=1)
    content_type = models.ForeignKey(ContentType, blank=True, null=True)
    content_object = generic.GenericForeignKey('content_type', 'object_id')

    created = models.DateTimeField(auto_now_add=True)
    modified = models.DateTimeField(auto_now_add=True, auto_now=True)

I'm newbie in Django REST API , I read documentation http://www.django-rest-framework.org/api-guide/parsers.html#fileuploadparser , but still don't undestand how to do it

Possible duplicate of Django Rest Framework File Upload

Dhia
– Dhia

2016-03-03 07:29:49 +00:00
Commented Mar 3, 2016 at 7:29 — Dhia
– Dhia, Commented Mar 3, 2016 at 7:29

JJD · Accepted Answer · 2015-04-14 14:43:07Z

25

First of all you need to define a parser in your view. This is because the API needs to know which headers to look for. Browsers transfer files as form-data, so you need to use the MultiPartParser and FormParser together. You can also use the FileUploadParser but you need to make sure your client is sending the correct HTTP headers.

from rest_framework.parsers import MultiPartParser, FormParser

class AssetAdd(APIView):
    parser_classes = (MultiPartParser, FormParser,)

Then, in the post method, your file will be present in the FILES QueryDict:

def post(self, request, format=None):
    my_file = request.FILES['file_field_name']
    filename = '/tmp/myfile'
    with open(filename, 'wb+') as temp_file:
        for chunk in my_file.chunks():
            temp_file.write(chunk)

    my_saved_file = open(filename) #there you go

edited Apr 14, 2015 at 14:43

JJD

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answered Jun 25, 2014 at 23:23

fixmycode

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8 Comments

blaz1988 Over a year ago

please can you explain me in more details,

blaz1988 Over a year ago

I added class AssetAdd(APIView): parser_classes = (MultiPartParser, FormParser,) def post(self, request, format=None): my_file = request.FILES['file_field_name'] print my_file

blaz1988 Over a year ago

when I tried to execute {"name": "San Francisco Bridge", "source": "assets/34/3492/3492AA/3492AA/source.jpg"} , but get error { "detail": "Multipart form parse error - Invalid boundary in multipart: None" }

blaz1988 Over a year ago

I tried curl -X POST 127.0.0.1:8000/api/v1/assets -d '{"name": "San Francisco Bridge", "source": "assets/34/3492/3492AA/3492AA/source.jpg"}' -H "Content-Type: multipart/form-data" but get error { "detail": "Multipart form parse error - Invalid boundary in multipart: None" } ???

fixmycode Over a year ago

@MarkWinterbottom from rest_framework.parsers import MultiPartParser, FormParser

|

Aula · Accepted Answer · 2019-07-18 14:41:02Z

Write your models like this:

from django.db import models
class PicModel(models.Model):
    file_to_be_uploaded = models.FileField(upload_to='/directory/where/you/what/to/upload/to')

if you uploading images then ImageField but install pillow by pip install pillow.

In you serializers.py assuming you are using rest_framework:

from rest_framework import serializers
from app_name.models import PicModel

class PicSerializer(serializers.ModelSerializer):
    class Meta:
        model = PicModel
        fields = '__all__' #or any way you may like to display you fields

In you views.py include assuming you are to using class-base views:

from app_name.models import PicModel
from app_name.serializers import PicModelSerializer
#other necessary imports

class PicList(APIView):
    def post(self, request, format=None):#or format can be json or api
        serializer = PicModelSerializer(data=request.data)
        if serializer.is_valid():
            serializer.save()
            ............more code

To test in json data write like:

{
    "file_to_be_uploaded":"//path//to//file//on//local//machine"
}

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