Deserializing Json to java classes using gson library

Question

enter image description here I have these two classes:

public class Root {
    public ProfileInfoResult ProfileInfoResult = new ProfileInfoResult();
}

public class ProfileInfoResult {
    public String joiningYear;
}

this is my json string which i have to deserialize:

{"ProfileInfoResult":{"joiningYear":"2009"}}

This is code to deserialize:

Gson gson = new Gson();
JSONObject obj = new JSONObject(responseString); //responseString= {"ProfileInfoResult":{"joiningYear":"2009"}}
Root resultObj = new Root();
String resStr = obj.toString();
try
{
    resultObj = gson.fromJson(resStr, Root.class);
}
catch(Exception e)
{
    Log.i("myyyy", e.getMessage());
    e.printStackTrace();
}

Java debug says that resultObj cannotbe resolved to a variable.

No error in the code but after executing this line resultObj = gson.fromJson(resStr, Root.class); resultObj cannotbe resolved to a variable in variables of debug section. — Yawar
– Yawar, Commented Jul 3, 2014 at 7:13
This code looks very reasonable, and based on your message your error probably doesn't have to do with JSON or Gson. Can you post the whole class, or confirm that the error happens within a line you posted? — Jeff Bowman
– Jeff Bowman, Commented Jul 3, 2014 at 7:14
What is this debug section? Are you using an IDE? Can you post a picture? — Sotirios Delimanolis
– Sotirios Delimanolis, Commented Jul 3, 2014 at 7:14

Sunit Kumar Gupta · Accepted Answer · 2014-07-03 07:31:14Z

1

String str = "{\"ProfileInfoResult\":{\"joiningYear\":\"2009\"}}";

    Root root = new Root();

    Gson gson = new Gson();
    root = gson.fromJson(str, Root.class);
    TextView b = new TextView(context);
    b.setText(root.ProfileInfoResult.joiningYear);

this is working fine.

answered Jul 3, 2014 at 7:31

Sunit Kumar Gupta

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5 Comments

Yawar Over a year ago

is that due to escape sequences missing in my string?

Sunit Kumar Gupta Over a year ago

from where you are getting your string, from any service or it is just hard coded?

Sunit Kumar Gupta Over a year ago

then escape sequences not an issue.

Yawar Over a year ago

I don't know why but it automatically start working.

Sunit Kumar Gupta Over a year ago

there was some error warning on this line Root resultObj = new Root();

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