Python: Get name of function which called this function

Question

Currently I can get the function name using this command:

sys._getframe().f_code.co_name

I want to put it in of function like this:

def func_name:
    return sys._getframe().f_code.co_name

this function always returns 'func_name'. Is it possible to get the name the function which is calling this function?

traceback gives you the whole stack - docs.python.org/2/library/traceback.html so I presume you can get what you want from there — doctorlove
– doctorlove, Commented Aug 27, 2014 at 11:02
It's worth noting that while you can do this (see afeldspar's answer), 99% of the time when you think you want it (except for purposes like debugging a mess of threading code, or learning about how Python works by exploration), you really don't. — abarnert
– abarnert, Commented Aug 27, 2014 at 11:12

afeldspar · Accepted Answer · 2014-08-27 11:03:38Z

2

If the code you posted is working for you, then try giving _getframe() an argument of 1. The argument tells which frame to return, and it defaults to 0; you want 1, meaning the frame that frame 0 was called from.

However, the "inspect" module may be what you want, if you need it to work across more implementations of Python.

answered Aug 27, 2014 at 11:03

afeldspar

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1 Comment

abarnert Over a year ago

Also, if you already have the current frame and want its parent, you can always use f_back to walk up the stack.

wim · Accepted Answer · 2014-08-27 11:18:43Z

1

Avoiding the use of sys._getframe:

import inspect

def bar():
    current_frame = inspect.currentframe()
    previous_frame = current_frame.f_back
    print previous_frame.f_code.co_name

def foo():
    bar()

foo()

answered Aug 27, 2014 at 11:18

wim

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