Transforming array into json with PHP

Question

I have this array

$params_array['application_id'] = 'xxxxxxxxx';
$params_array['v'] = 1.20;
$params_array['src'] = 'http://www.google.com/logos/2011/yokoyama11-hp.jpg';
$params_array['functions']['name'] = 'blur';
$params_array['functions']['params']['radius'] = '0.0';
$params_array['functions']['params']['sigma'] = '2.0';
$params_array['functions']['save']['image_identifier'] = 'MY_CLIENT_ID';

I need to transform it into json.

So I am doing this:

$json = json_encode($params_array,JSON_UNESCAPED_SLASHES);

The result is

{"application_id":"xxx","v":1.2,"src":"http://www.google.com/logos/2011/yokoyama11-hp.jpg","functions":{"name":"blur","params":{"radius":"0.0","sigma":"2.0"},"save":{"image_identifier":"MY_CLIENT_ID"}}}

but, the receiver API of that json wants it to be formed slightly different, like this:

{"application_id":"xxx","v":1.2,"src":"http://www.google.com/logos/2011/yokoyama11-hp.jpg","functions":[{"name":"blur","params":{"radius":"0.0","sigma":"2.0"},"save":{"image_identifier":"MY_CLIENT_ID"}}]}

The difference: after "functions": there is this bracket [, and it's closed at the end.

PHP somehow does not create the json with this bracket.

How can I get PHP to create the json with those brackets?

The receiver API is http://www.blitline.com/docs/quickstart

The output from json_encode is correct JSON-syntax. Review your receiver API so that this is correct. Try your different versions here; jsoneditoronline.org — Sander
– Sander, Commented Aug 27, 2014 at 12:31

Lajos Veres · Accepted Answer · 2014-08-27 12:33:06Z

2

You should prepare your structure this way:

$params_array['application_id'] = 'xxxxxxxxx';
$params_array['v'] = 1.20;
$params_array['src'] = 'http://www.google.com/logos/2011/yokoyama11-hp.jpg';
$params_array['functions'][0]['name'] = 'blur';
$params_array['functions'][0]['params']['radius'] = '0.0';
$params_array['functions'][0]['params']['sigma'] = '2.0';
$params_array['functions'][0]['save']['image_identifier'] = 'MY_CLIENT_ID';

(Making functions to a number indexed array.)

answered Aug 27, 2014 at 12:33

Lajos Veres

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Comments

Justinas · Accepted Answer · 2014-08-27 12:39:06Z

1

So receiver expects functions to be array objects, but you pass single object instead. Change $params_array['functions']['name'] to $params_array['functions'][$functionIndex]['name']

edited Aug 27, 2014 at 12:39

answered Aug 27, 2014 at 12:32

Justinas

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3 Comments

Eduscho Over a year ago

Will do, but stackoverflow says wait 7 minutes

FuzzyTree Over a year ago

wouldn't this create a new array for every property besides name? params and save should be in the same array as name

Justinas Over a year ago

Yes, so you have to put explicit index

Raja · Accepted Answer · 2014-08-27 12:33:11Z

0

Try this

$params_array['application_id'] = 'xxxxxxxxx';
$params_array['v'] = 1.20;
$params_array['src'] = 'http://www.google.com/logos/2011/yokoyama11-hp.jpg';
$function_array['name'] = 'blur';
$function_array['params']['radius'] = '0.0';
$function_array['params']['sigma'] = '2.0';
$function_array['save']['image_identifier'] = 'MY_CLIENT_ID'; 
$params_array['functions'] = array($function_array);

Reason: JSON_ENCODE will treat an Array as JSON OBJECT if it is like Key=>Value and it will treat as json array if it is index based like [0] => value

answered Aug 27, 2014 at 12:33

Raja

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Comments

stonyau · Accepted Answer · 2014-08-27 12:40:43Z

0

Alright, run this example then you'll know how to achieve it.

$params_array = array();
$params_array['application_id'] = 'xxxxxxxxx';
$params_array['another_array'] = array("A","B","C");
echo json_encode($params_array );

Result: {"application_id":"xxxxxxxxx","another_array":["A","B","C"]}

answered Aug 27, 2014 at 12:40

stonyau

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Comments

Thomas P. · Accepted Answer · 2015-04-18 16:45:05Z

0

You can try to use the flag JSON_FORCE_OBJECT if you have PHP 5.4.0 or later :

$json = json_encode($params_array,JSON_UNESCAPED_SLASHES + JSON_FORCE_OBJECT);

edited Apr 18, 2015 at 16:45

answered Aug 27, 2014 at 12:32

Thomas P.

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2 Comments

Veerendra Over a year ago

Notice: Use of undefined constant JSON_UNESCAPED_SLASHES - assumed 'JSON_UNESCAPED_SLASHES'

Thomas P. Over a year ago

... In PHP <5.4.0 . This constant, which the author included in his question, is available since PHP 5.4.0. php.net/manual/en/json.constants.php

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