Problems parsing JSON in Java

Question

I have this json:

[{
    "name": "prog 1",
    "show": [{
        "name": "n1",
        "time": "01.10 "
    }, {
        "name": "n2",
        "time": "01.35 "
    }]
}, {
    "name": "prog 2",
    "show": [{
        "name": "n1",
        "time": "01.10 "
    }, {
        "name": "n2",
        "time": "01.35 "
    }]
}]

Now trying to parse it in Java like:

JSONObject json=new JSONObject(json_str);

throws an Exception, since it doesn't begin with {, but [ since it's an array. I can parse this without problem in js, but aparently I cannot load an JSONArray with this string...

check this -> stackoverflow.com/questions/5650171/… if it can help. — akshayb
– akshayb, Commented Sep 10, 2014 at 12:30
Sometimes it gets easier for us to help you if you not only describe the exception you got, but also include the stacktrace in your question. — DanielBarbarian
– DanielBarbarian, Commented Sep 10, 2014 at 12:31
Go to json.org and study the syntax. You have an array of objects (and the objects contain arrays). You need to use JSONArray. — Hot Licks
– Hot Licks, Commented Sep 10, 2014 at 12:39

BatScream · Accepted Answer · 2014-09-10 12:43:14Z

1

use: JSONArray objArray = new JSONArray (json_str);

// to access the individual objects inside the array:

for(int i=0;i<objArray.length();i++)
{
  JSONObject obj = objArray.getJSONObject(i);
}

edited Sep 10, 2014 at 12:43

answered Sep 10, 2014 at 12:37

BatScream

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blackSmith · Accepted Answer · 2014-09-10 12:37:53Z

1

Have you tried this:

    JSONArray arr = new JSONArray(stringWithContent);

Then access it like :

    for(int i = 0; i<arr.length();i++){
        System.out.println(arr.get(i));
    }

answered Sep 10, 2014 at 12:37

blackSmith

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Hardik Visa · Accepted Answer · 2014-09-10 12:46:51Z

0

You can try following code

JSONObject jObject  = new JSONObject(json_str);
JSONArray array = jObject.getJSONArray("show");    
for(int i = 0 ; i < array.length() ; i++)
{
    System.out.println(array.getJSONObject(i).getString("name"));
    System.out.println(array.getJSONObject(i).getString("time"));
}

It will helpful ...

answered Sep 10, 2014 at 12:46

Hardik Visa

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