def reveal():
guessright = 0
for letter in secretword:
if letter == usertry:
guessright = guessright + 1
print usertry,
else:
print "_",
return guessright
reveal()
When using reveal() something like _ _ _ _ a _ will be printed by the for loop- is there a way of converting what it prints into a string, or getting the function to return 2 outputs, the integer guessright, and the stuff that was printed while reveal() was running?
Sure, there are lots of ways -- The simplest is to use a list to hold the data (appending new data rather than printing) and then ''.join it at the end:
def reveal():
text = []
guessright = 0
for letter in secretword:
if letter == usertry:
guessright = guessright + 1
text.append(usertry)
else:
text.append('_')
return guessright, ''.join(text)
reveal()
Here I return a tuple which is python's way of returning multiple values. You can unpack the tuple in assignment if you wish:
guessright, text = reveal()
getting the function to return 2 outputs
def reveal():
guessright = 0
show = []
for letter in secretword:
if letter == usertry:
guessright = guessright + 1
show.append(usertry)
else:
show.append("_")
return guessright, ''.join(show)
reveal()
def reveal():
guessright = 0
result = ""
for letter in secretword:
if letter == usertry:
guessright = guessright + 1
result += usertry
else:
result += "_"
return guessright,result
reveal()
In python you can return two outputs by using a tuple.
In your code, you could return in by doing something like:
def reveal():
guessright = 0
text = ''
for letter in secretword:
if letter == usertry:
guessright = guessright + 1
text += usertry,
else:
text += "_",
print text
return (guessright, text)
(guessright, text) = reveal()
Then you can access guessright and text outside of the scope of `reveal()'.
