How to write if include? condition in JavaScript?
My sample code is here:
var a = ['red', 'green', 'blue', 'yellow'];
if (a.include("red" ))
{
alert(a);
}
It gives the following error:
SyntaxError: missing : in conditional expression
Add a comment
|
5 Answers
You can use $.inArray() in jQuery
$(function(){
var a = ['red', 'green', 'blue', 'yellow'];
if ($.inArray( "red", a )>=0)
{
alert(a);
}
});
Comments
plain vanilla javascript
you can use some to check for the existence
The some() method tests whether some element in the array passes the test implemented by the provided function.
var result = ['red', 'green', 'blue', 'yellow'].some(function(item,index,arr){
return item === 'red'
});
if (result === true)
{
alert(a);
}
Comments
Try using $.inArray() as shown.
var a = ['red', 'green', 'blue', 'yellow'];
if($.inArray("red",a) > -1)
{
alert(a);
}
EDIT :-
Comments
It 's .includes() Not .include()
https://www.geeksforgeeks.org/javascript-string-includes-method/
Comments
I think you are trying to find a ruby alternative. Are you checking whether red is a member of array ?
You can use Array.indexOf()
then you may do it like
if (a.indexOf("red" )=!-1) {
Sample code below:
var a = ['red', 'green', 'blue', 'yellow'];
//will return -1 if not found in array. otherwise will give you the index
var indexOfRed = a.indexOf("red");
if (indexOfRed!=-1)
{
alert("red was found at index - "+indexOfRed);
}