Getting String cannot be cast into Integer error

Question

I am getting this error, but don't know why. Here

feedArray.get(mJazzy.getCurrentItem()).get("TotalCount_Smasheys")

returns an Object type. I followed this link to cast Object to Integer.

Screen 1: Here I inspected:

feedArray.get(mJazzy.getCurrentItem()).get("TotalCount_Smasheys")

and got value:

screen 1

Screen 2: Here I inspected: (Integer)(feedArray.get(mJazzy.getCurrentItem()).get("TotalCount_Smasheys")) and it throws exception:

screen 2

EDIT: It is very confusing. feedArray.get(mJazzy.getCurrentItem()).get("TotalCount_Smasheys") returns me an Object, which is actually an Integer, so I can't use (String) on it.

Kasim Rangwala · Accepted Answer · 2014-09-24 19:17:08Z

1

first use String.trim() Then, instead of casting to Integer Use Integer.parseInt() or Integer.valueOf()
It'll might help.

answered Sep 24, 2014 at 19:17

Kasim Rangwala

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1 Comment

Kasim Rangwala Over a year ago

so, use Integer.parseInt(String.valueOf(<your variable>)) this will work on Object type

Pedro Oliveira · Accepted Answer · 2014-09-24 19:12:47Z

0

That's because the string has spaces. Remove the spaces from the string first and then use Integer.parseInt() to change it to integer.

You can use string.trim() or string.replace(" ","") to remove whitespaces.

answered Sep 24, 2014 at 19:12

Pedro Oliveira

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8 Comments

berserk Over a year ago

Check screen 1, it is an object with count 2 i.e. "3" and "1"

Pedro Oliveira Over a year ago

that's not "3" and "1". That's "31 ". That's a lot different.

Dave Newton Over a year ago

No, it's because you can't cast a string to an integer.

Pedro Oliveira Over a year ago

That's why I've put Integer.parseInt() in my solution.

berserk Over a year ago

As I mentioned, feedArray.get(mJazzy.getCurrentItem()).get("TotalCount_Smasheys") gives me Object not String.

|

yrazlik · Accepted Answer · 2014-09-24 19:24:16Z

0

It lloks like "31" is not an integer but a string. Did you try

int i = Integer.valueOf((String) your_object);

answered Sep 24, 2014 at 19:24

yrazlik

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Comments

Guilherme · Accepted Answer · 2014-09-26 17:51:18Z

0

The method

feedArray.get(mJazzy.getCurrentItem()).get("TotalCount_Smasheys")

is returning a String, not an Integer.

Convert it to integer using Integer.parseInt():

String countString = (String) feedArray.get(mJazzy.getCurrentItem()).get("TotalCount_Smasheys");
Integer countInt = Integer.parseInt(countString);

edited Sep 26, 2014 at 17:51

answered Sep 24, 2014 at 19:28

Guilherme

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5 Comments

Guilherme Over a year ago

It clearly is not an Integer otherwise it wouldn't crash that way. Did you try my answer? What error did you get using it?

berserk Over a year ago

Actually feedArray is an ArrayList of type ParseObject. And ParseObject.get("key") returns an "Object", not an Integer. But the value is actually an Integer, so the Object it returns automatically becomes Integer. Hope u understand what I said lol.

Guilherme Over a year ago

Did you try my answer?

Guilherme Over a year ago

Ok, you need to do what Eclipse is suggesting (and I also forgot to do, sorry for that): cast the string. I've updated my answer.

berserk Over a year ago

The problem is that the Object can be anything, String or Integer. If it returns Integer, then it will cause error here.

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