How to add option to javascript RegExp object

Question

I have created a regular expression with a variable, which is dynamically passed.

new RegExp("(" + variable_name + ":\\((.*?)\\))");

It perfectly results in /(ABC:\((.*?)\))/ (if variable_name is ABC)

But, If I pass an option as

new RegExp("(" + variable_name + ":\\((.*?)\\))") + "g",

it gives me the regular expression in string format

"/(ABC:\((.*?)\))/g"

and the match() function fails. Is there any good way to pass option without converting the expression into string.

Thanks for the answer guys. Great answer to a silly question. :( — Abhi
– Abhi, Commented Oct 7, 2014 at 11:12

Avinash Raj · Accepted Answer · 2014-10-07 11:08:03Z

2

You need to include the g (global modifier) within the brackets.

new RegExp("(" + variable_name + ":\\((.*?)\\))", "g");

answered Oct 7, 2014 at 11:08

Avinash Raj

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Comments

aelor · Accepted Answer · 2014-10-07 11:08:27Z

2

use this :

new RegExp("(" + variable_name + ":\\((.*?)\\))", "g");

answered Oct 7, 2014 at 11:08

aelor

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Academia · Accepted Answer · 2014-10-07 11:11:14Z

1

You can include whatever option you need:

var options = "g"; //g, m, i, or combination of them
new RegExp("(" + variable_name + ":\\((.*?)\\))", options);

Hope it's useful!

answered Oct 7, 2014 at 11:11

Academia

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