0 
class liste
{
    int numara;
    String ad;
    String soyad;
    liste sonraki;
} 

public static void main(String[] args) throws IOException
{
    BufferedReader br = new BufferedReader(new FileReader("C:\\bagli.txt"));
    BufferedReader reader = null;  
    String s;
    Scanner klavye = new Scanner(System.in);
    listeler mylist = new listeler();
    while(br.ready())
    {   
        s=br.readLine();

        String[] firstLine = s.split("#");
        liste kayıt = new liste();
        kayıt.numara = Integer.parseInt(firstLine[0].trim());
        kayıt.ad =  firstLine[1].trim();
        kayıt.soyad =  firstLine[2].trim();
        mylist.ekle(kayıt);
    }

I get the following error

Exception in thread "main" java.lang.NumberFormatException: For input string: "33"

on the following line:

kayıt.numara = Integer.parseInt(firstLine[0].trim());

What should be the correct code ? bagli.txt in

33#ahmet#korkusuz

44#hanife#demir

66#murat#tok
Improve this question
8
  • 1
    what is listeler and why aren't you using List<MyElement> list = new ArrayList<MyElement>(); to store a list of elements? Commented Oct 10, 2014 at 11:52
  • 3
    It would appear that firstLine[0] has some non-printable character in it (since "33" can, of course, be parsed -- so there's something we can't see in the exception message). Use a debugger to single-step through the code to that line and see what exactly the string in firstLine[0] is, so you know what characters to remove from it. Commented Oct 10, 2014 at 11:54
  • why don't you print and check the value of firstLine[0].trim() Commented Oct 10, 2014 at 11:55
  • I suspect that the number in the file is "33" with extra quotes and not just 33 without quotes. Commented Oct 10, 2014 at 11:56
  • 1
    @Davio: Good thought, but the quotes are added by the exception message. If you try to parse it with quotes, you get Exception in thread "main" java.lang.NumberFormatException: For input string: ""33"" Commented Oct 10, 2014 at 11:58
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