Example array
$myArray[0] = array('23', null, '43', '12');
$myArray[1] = array(null, null, '53', '19');
$myArray[2] = array('12', '13', '14', null);
All nulls should be replaced with 0. I was hoping someone would have an efficient way of doing this, perhaps a built in PHP function that I am unaware of.
You could use the array_walk_recursive function, with a callback function that would replace null by 0.
$myArray[0] = array(23, null, 43, 12);
$myArray[1] = array(null, null, 53, 19);
$myArray[2] = array(12, 13, 14, null);
Note : I supposed you made a typo, and your arrays are not containing only a string, but several sub-elements.
array_walk_recursive($myArray, 'replacer');
var_dump($myArray);
function replacer(& $item, $key) {
if ($item === null) {
$item = 0;
}
}
Note that :
=== operator for the comparisonarray
0 =>
array
0 => int 23
1 => int 0
2 => int 43
3 => int 12
1 =>
array
0 => int 0
1 => int 0
2 => int 53
3 => int 19
2 =>
array
0 => int 12
1 => int 13
2 => int 14
3 => int 0
$item should not be an array : I'm using the recursive function ;-) which means the callback is called for the sub-elements (integers), and not the elements (arrays) themselves.
If the single quotation marks are unintentional, and the arrays have integers and null values:
for ($i = 0; $i < count($myArray); $i++)
{
if ($myArray[$i] == null) $myArray[$i] = 0;
}
From PHP7.4 and higher, you can use arrow function syntax to make iterated calls of intval() on each row. This is safe to use on your data because none of the input values will be damaged by unconditionally casting them to int type data.
Code: (Demo)
var_export(
array_map(fn($row) => array_map('intval', $row), $myArray)
);
