Why is instance variable not getting recognized

Question

I have the following class in Python.

import os,ConfigParser

class WebPageTestConfigUtils:

    def __init__(self, configParser=None, configFilePath=None):
        self.configParser = ConfigParser.RawConfigParser()
        self.configFilePath = (os.path.join(os.getcwd(),'webPageTestConfig.cfg'))

    def initializeConfig(self):
        configParser.read(configFilePath)
        return configParser

    def getConfigValue(self,key):
        return configParser.get('WPTConfig', key)

def main():
webPageTestConfigUtils = WebPageTestConfigUtils()
webPageTestConfigUtils.initializeConfig()
webPageTestConfigUtils.getConfigValue('testStatus')

if  __name__ =='__main__':
main()

Upon execution . This gives me the error.

NameError: global name 'configParser' is not defined.

Why is python not able to recognize the instance variable here. ~
~

You don't need extra ( ) around os.path.join(os.getcwd(), 'webPageTestConfig.cfg') — Burhan Khalid
– Burhan Khalid, Commented Nov 4, 2014 at 6:30

NPatel · Accepted Answer · 2014-11-04 05:57:01Z

3

You are defining

...
self.configParser = ConfigParser.RawConfigParser()
...

And accessing using

...
configParser.read(configFilePath)
...

You have to access as self.configParser.

answered Nov 4, 2014 at 5:57

NPatel

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Comments

Ayush · Accepted Answer · 2014-11-04 06:37:51Z

1

That's expected. In your code, python will not be able to access class members without self. Here is the correct code:

def initializeConfig(self):
    self.configParser.read(self.configFilePath)
    return self.configParser

def getConfigValue(self,key):
    return self.configParser.get('WPTConfig', key)

edited Nov 4, 2014 at 6:37

answered Nov 4, 2014 at 6:25

Ayush

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