issue with adding two-dimensional array to string python

Question

please help me. I have two-dimensional array example :

self.history = [['23295', u'0.0500',  u'0.0700', u'0.0600', u'0.0600'],['23295', u'0.0500', u'0.0700', u'0.0600', u'0.0600']]

i try parsing him and get string but have syntax error, please advice.

for i in  range(int(cac)):
    returning = returning + "\""+str(date_arr[i])+","+ str(self.history[0 for x in range(len(self.history))][i])+"+"

in output i need have somethings like :

"somedate,'23295','23295'" + "somedate,u'0.0500',u'0.0500'" + "somedate,u'0.0700',u'0.0700'"...

the problem is here: [0 for x in range(len(self.history))] — user1922137
– user1922137, Commented Nov 13, 2014 at 17:43
i have in output somethings like that : "2014-11-13 18:44,[0]" — user3731374
– user3731374, Commented Nov 13, 2014 at 17:45

score 1 · Accepted Answer · 2014-11-13 18:04:56Z

1

You have to use two for loops:

for x in range(len(self.history)):
    for i in  range(int(cac)):
        returning = returning + "\""+str(date_arr[i])+","+ str(self.history[x][i])+"+"

Note that your code [x for x in range(len(self.history))] generates a list whereas you need an integer to index your list

edited Nov 13, 2014 at 18:04

answered Nov 13, 2014 at 17:44

user1922137

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3 Comments

user3731374 Over a year ago

thanks, but as result i have : "2014-11-13 18:45,[0]"2014-11-13 18:46,[0]"2014-11-13 18:47,[0]"2014-11-13 18:48,[0]"2014-11-13 18:49,[0]"2014-11-13 18:50,[0]"2014-11-13 18:51,[0]"2014-11-13 18:52,[0]"...

user3731374 Over a year ago

thanks really for the help, but there is back (example): self.history[0][0], self.history[1][0], self.history[0][1], self.history[1][1], but need in this order : self.history[0][0], self.history[0][1], self.history[0][1], self.history[1][1]... I hope you understand and again thanks

user1922137 Over a year ago

@user3731374 simply change the position of for loops as I edited my answer

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