php group array together based on key value being the same

Question

I have the following array

Array
(
[0] => Array
    (
        [id_product_option] => 1
        [id_option] => 1
        [id_product] => 3
        [option_value] => White
        [option_name] => color

    )

[1] => Array
    (
        [id_product_option] => 2
        [id_option] => 2
        [id_product] => 3
        [option_value] => 9oz
        [option_name] => size

    )

[2] => Array
    (
        [id_product_option] => 3
        [id_option] => 1
        [id_product] => 3
        [option_value] => Blue
        [option_name] => color

    )

)

What i need to do is loop through it and find the ones where the id_option values match and group them into a new array that should look like

Array
(
[0] => Array
    [0] => Array
        (
            [id_product_option] => 1
            [id_option] => 1
            [id_product] => 3
            [option_value] => White
            [additional_cost] => 0
            [is_active] => 1
            [created_on] => 2014-11-15 01:29:35
            [option_name] => color
            [option_text] => Color
        )

    [1] => Array
        (
            [id_product_option] => 3
            [id_option] => 1
            [id_product] => 3
            [option_value] => Blue
            [additional_cost] => 0
            [is_active] => 1
            [created_on] => 2014-11-15 01:29:35
            [option_name] => color
            [option_text] => Color
        )

[1] => Array
    (
        [id_product_option] => 2
        [id_option] => 2
        [id_product] => 3
        [option_value] => 9oz
        [additional_cost] => 0
        [is_active] => 1
        [created_on] => 2014-11-15 01:29:35
        [option_name] => size
        [option_text] => Size
    )


)

where the options with id_option 1 are grouped together

I tried the following but no luck

    $groupOptions = array();
    $prev = "";
    foreach($productOptions as $key=>$options) {
        $id_option = $options['id_option'];

        if($id_option != $prev) {
            $groupOptions[] = $productOptions[$key];
        }

        $prev = $id_option;
    }

Why are you marking this down i dont understand. Better if you just dont say anything. This place is meant to help people not just think a question is stupid and mark it down — Yeak
– Yeak, Commented Nov 19, 2014 at 18:37
I don't know who down-voted your question, but it was probably before you had shared what you had tried. — Jay Blanchard
– Jay Blanchard, Commented Nov 19, 2014 at 18:39

Marc B · Accepted Answer · 2014-11-19 18:48:03Z

1

You should use that id_option as the key in your new array, otherwise you're stuck having to hunt through the new array to find where the matching items are, which you're ALREADY doing in the first loop

$newarray = array();
foreach($oldarray as $item) {
   $newarray[$item['id_option']][] = $item;
}

answered Nov 19, 2014 at 18:48

Marc B

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Comments

Halayem Anis · Accepted Answer · 2014-11-19 18:59:46Z

0

I have tested with you example and seems to work fine :

$notFactored; # you should provide here your input array
$factored = array();
foreach($notFactored as $nf) {
    $found = FALSE;
    foreach($factored as &$f) { # passed by address !
        if(!empty($f[0]) && $nf['id_option'] == $f[0]['id_option']) {
            $f[] = $nf;
            $found = TRUE;
            break;
        }
    }
    if(!$found) {
        $factored[count($factored)][] = $nf;
    }
}
print 'my factored array : ' . print_r($factored);

Hope that Helps :)

answered Nov 19, 2014 at 18:59

Halayem Anis

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