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I have a basic question. Say I have a Uint16Array and I have number 4 in it. 

data_16=new Uint16Array([4]);

Now I have a length 1 and byteLength 2;

how do i convert this to Uint8Array.

I do not want to create a new view. 

data_8 = new Uint8Array(data_16)

If I do this I get array length 1 and byteLength 1. This is not what I want.

I need to stretch that 16 bit value in 16array into 8 bit values so that 8bit array so it would end up with 2 values int 8 bit array.

I can just create a funtion which converts with shif and to all that stuff. But Can it be done with Array manipulation only?

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2 Answers 2

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16

You can use the buffer property, i.e. data_8 = new Uint8Array(data_16.buffer, data_16.byteOffset, data_16.byteLength).

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1 Comment

I suggest new Uint8Array(data_16.buffer, data_16.byteOffset, data_16.byteLength), because in the general case there's no guarantee that data_16 views all of its backing ArrayBuffer.
2

Would like to note that the current accepted answer may not work because of the byte order is platform dependent.

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