Deserialize JSON object to String Android

Question

I am trying to implement deserialization to parse json object as a string, but my custom deserializable class is not being called.

JSON which needs to be parsed

{

 "status": true,
 "student": [
    {
        "id": 1,
        "name": "",
        "age": "",
         "title": "",

    }
]
}

My Deserializable class

public class MyDeserializer implements JsonDeserializer<StudentData> {

@Override
public StudentData deserialize(JsonElement je, Type type, JsonDeserializationContext jdc) {
    try {

        String content = je.getAsJsonObject().get("student").getAsString();

        return new Gson().fromJson(content, StudentData)
    } catch (Exception e) {
        e.printStackTrace();
        return null;
    }
}
}

Register my deserializer:-

MyDeserializer myDeserializer = new MyDeserializer();
Gson gson = new GsonBuilder().registerTypeAdapter(NotificationResponse.class, myDeserializer).create();
mRestAdapter = new RestAdapter.Builder().setServer(baseUrl).setConverter(new GsonConverter(gson)).setLogLevel(RestAdapter.LogLevel.FULL).setRequestInterceptor(new RequestInterceptor() 
             {
                @Override
                public void intercept(RequestFacade requestFacade) {
                }
            }).build();

My issue is that the custom deserializer is not being called. — swati
– swati, Commented Dec 5, 2014 at 6:34
to correctly implement you should use the same "gson" object you created to call "fromGson()" function ? otherwise initialising it every time like new Gson() will not call your Desiralizer class — Shubhang Malviya
– Shubhang Malviya, Commented Dec 5, 2014 at 7:07

Shubhang Malviya · Accepted Answer · 2014-12-05 06:41:09Z

0

I think this tutorial will help you implement a Deserializer(and might introduce some new concepts)

Try it, and see if it work for you!

answered Dec 5, 2014 at 6:41

Shubhang Malviya

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Comments

Jared Rummler · Accepted Answer · 2014-12-05 06:48:44Z

0

For something that simple I don't think adding Gson as a dependency is worth it.

Example:

JSONObject jObj = new JSONObject(theJsonYouPostedAbove);
boolean status = jObj.getBoolean("status");
JSONArray jArr = jObj.getJSONArray("student");
for (int i = 0; i < jArr.length(); i++) {
    JSONObject jo = jArr.getJSONObject(i);
    int id = jo.getInt("id");
    String name = jo.getString("name");
    ...
}

answered Dec 5, 2014 at 6:48

Jared Rummler

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