Converting Time Output to a Float Variable (Python)

Question

from Tkinter import *
from datetime import datetime
from datetime import timedelta
import math

rate1 = str(35.34) 
amp = 2.40
pmp = 2.50



signOnSun1 = raw_input("What time did you sign on Sunday: ");
signOffSun1 = raw_input("What time did you sign off Sunday: ");

if (signOnSun1 < 0600):
    rate1 = rate1 + amp
elif (signOnSun1 > 1100):
    rate1 = rate1 + pmp
elif (signOffSun1 > 1800):
    rate1 = rate1 + pmp
else:
    rate1 = 35.34

FMT = '%H%M'    
timeWorkedSun1 =  ( (datetime.strptime(signOffSun1, FMT)) -  (datetime.strptime   (signOnSun1, FMT)))

* I want to convert timeWorkedSun1 to a float so i can multiply it with rate1 but it seems to be the bane of my life. Any ideas?*

so the output i receive is in the format 00:00:00. which is great. but for example if the format says 8:00:00 i want to be able to multiply that with a float. for example 8:00:00 * 34.45 doesn't work. So I'm basically calculating the hours i work per day and multiplying that with my hourly rate. thats the aim — Deren Devrimol
– Deren Devrimol, Commented Dec 20, 2014 at 5:40

Alex Martelli · Accepted Answer · 2014-12-20 05:46:36Z

3

timeWorkedSun1 is of type datetime.timedelta. Call its total_seconds method to translate it into a number of second (then divide by 3600 to get it in hours-and-fractions). I.e:

time_mul_by_hourly_rate = (timeWorkedSun1.total_seconds() / 3600.0) * rate1

answered Dec 20, 2014 at 5:46

Alex Martelli

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Comments

Gagravarr · Accepted Answer · 2014-12-20 05:44:46Z

1

Assuming what you want to do is ask a user to enter two hours:minutes figures, and calculate the hours + fractions of hours between them, then using datetime as you do now, you'd do something like (simplified):

signOn = "09:15"
signOff = "15:45"

FMT = "%H:%M"
timeWorkedSun =  datetime.strptime(signOff, FMT) -  datetime.strptime(signOn, FMT)

# timeWorkedSun is now a datetime.timedelta
fractionHours = timeWorkedSun.total_seconds()/60.0/60

Alternately, without datetime code, we could do:

signOn = "09:15"
signOff = "15:45"

signOnP = [int(n) for n in signOn.split(":")]
signOffP = [int(n) for n in signOff.split(":")]

signOnH = signOnP[0] + signOnP[1]/60.0
signOffH = signOffP[0] + signOffP[1]/60.0

hours = signOffH - signOnH

However, that'll fail if someone started at 6pm on one day and ended at 3am the next day, so you might want to rethink your logic

answered Dec 20, 2014 at 5:44

Gagravarr

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2 Comments

Alex Martelli Over a year ago

2 big issues: timeWorkedSun.seconds is NOT callable (it's an attribute!) AND it's not the total number of seconds -- try datetime.timedelta(days=1).seconds ...!-). What you need is .total_seconds() as in my answer. You're right about time shifts passing midnight, though...

Deren Devrimol Over a year ago

you my friend are a freaked genius!

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