how to print dynamic variable value in php [duplicate]

Question

how to get value or same name variable but end with different index

 $item1='100';
 $item2='200';
 $item3='300';
 $item4='400';
 $item5='500';

 for ($i=1;$i<4;$i++){
    echo '--'.$($item.$i); // or echo '--'.$.'item'.$i);
 }

i have variable $item1,2,3,.... i don't know how many item variable i got . i got total no of item variable so i want to go with loop and print all item variable value . i write above code but error occur . any one know how to get each item value ????

in my case array not possible . other wise with array all is very simple — Affan
– Affan, Commented Dec 31, 2014 at 11:38
@Affan explain why you can't save values to array indexes, but can save them to random named variables... — Justinas
– Justinas, Commented Dec 31, 2014 at 11:39
i don't know why people give negative marking without give any solution . solution is there . i place $($itme) instead of {} . — Affan
– Affan, Commented Dec 31, 2014 at 11:43

GautamD31 · Accepted Answer · 2014-12-31 11:38:37Z

2

You can try like

echo '--'.${"item" . $i};

Refer this.And better you use an array like

$item[1]='100';
$item[2]='200';
$item[3]='300';
$item[4]='400';
$item[5]='500';

answered Dec 31, 2014 at 11:38

GautamD31

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Comments

Barmar · Accepted Answer · 2014-12-31 11:39:17Z

0

A better approach would be to use an array. But if you need to use dynamic variables, the syntax is:

echo '--'.${$item.$i};

See Variable Variables.

answered Dec 31, 2014 at 11:39

Barmar

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1 Comment

Affan Over a year ago

yes i understand but i work with payment method and it provide me only variable and each time different no of variable so i need this . after get this i will create array from this and do my further process . thanks for help @Barmar

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