Replace Values In a List with Multiple Rows (Python 2.7) [duplicate]

Question

I've been searching around for a while and not found the solution. Any help is very much appreciated!

Problem: I'd like to find and replace all percentage symbols ("%") in a multiple row list. The below example is a short version of my actual data which has many more rows and columns. Here's the example:

x = [['name', 'col1', 'col2'],
['a', '43.63%', '2'],
['b', '14.20%', '3.5%'],
['c', '10%', '3.4%']]

Desired outcome:

x = [['name', 'col1', 'col2'],
['a', '43.63', '2'],
['b', '14.20', '3.5'],
['c', '10', '3.4']]

My code:

for row in x:
    for item in row:
        item = item.replace("%", "")
print x

I thought this would replace each item with the new string; however, when I now print x I get the original list with "%". Please could anyone see where I'm going wrong? Thanks in advance!

Reut Sharabani · Accepted Answer · 2015-01-31 23:52:25Z

2

You need to actually replace the item in the list.

Strings are immutable so you're creating a new item and basically not doing anything with it here:

# create wanted string, but where should it go?
item = item.replace("%", "")

You can use enumerate for doing what you want:

for row in x:
    for index, item in enumerate(row):
        # create string *and update row*
        row[index] = item.replace("%", "")
print x

edited Jan 31, 2015 at 23:52

answered Jan 31, 2015 at 23:44

Reut Sharabani

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