Passing a value in javascript

Question

I'm trying the tutorial from infotuts here: http://www.infotuts.com/ajax-table-add-edit-delete-rows-dynamically-jquery-php/

And there's a javascript like this:

 $(function(){
 $.ajax({
         url:"DbManipulate.php",
                  type:"POST",
                  data:"actionfunction=showData",
        cache: false,
        success: function(response){

          $('#demoajax').html(response);
          createInput();

        }

       });

Now I want to add a parameter so that the line: url:"DbManipulate.php" becomes url:"DbManipulate.php?q=[some value]

I tried to alter the script like this:

 var cat=2;

 $(function(){
 $.ajax({
         url:"DbManipulate.php?q="+cat.val(),
                  type:"POST",
                  data:"actionfunction=showData",
        cache: false,
        success: function(response){

          $('#demoajax').html(response);
          createInput();

        }

       });

But it doesn't work. The variable cat never gets into the function. How to pass the variable "cat" so that the DbManipulate.php file receives the $q variable and I can use it using $_GET?

Thank you

you are using POST, when you tack a variable to the end of the url that is a GET function. In my experience that doesnt work. You should add variable cat to your data that you send (POST) — Adam Joseph Looze
– Adam Joseph Looze, Commented Feb 1, 2015 at 4:21
there could be more errors, but try changing your data: to data:"actionfunction=showData&q="+cat.val()", — Adam Joseph Looze
– Adam Joseph Looze, Commented Feb 1, 2015 at 4:23
In your altered script, var cat=2; is an integer, so you don't need to use .val() to get the value. It should be just url:"DbManipulate.php?q="+cat,. But that will only work if you send it with type GET as mentioned above. — dloewen
– dloewen, Commented Feb 1, 2015 at 4:27

A l w a y s S u n n y · Accepted Answer · 2015-02-01 04:41:43Z

1

Try simply this way to sent your data variable(cat) using GET Method

var cat=2;
$(function(){
 $.ajax({
         url:"DbManipulate.php",
         type:"GET",
         data:{actionfunction:showData,cat:cat},
         cache: false,
         success: function(response){
          console.log(response);
          $('#demoajax').html(response);
          createInput();
        }
       });

 // in DbManipulate.php, try to catch cat using $_GET like this
  $cat=$_GET['cat'];
 //do further processing

EDIT

cat=2;
url="DbManipulate.php";
function yourFunc(cat,url){
$.ajax({
    type: "GET",
    url: url+'?q='+cat,
    dataType: "json",
    cache: false,
    success: function (response) {
        $('#demoajax').html(response);
              createInput();
    }
});
}
//in DbManipulate.php 
 $cat=$_GET['q'];

More Info:http://api.jquery.com/jquery.ajax/

edited Feb 1, 2015 at 4:41

answered Feb 1, 2015 at 4:25

A l w a y s S u n n y

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