Reg Exp for string in Javascript

Question

i am looking for create a regular exp in JavaScript to look for patterns like ${.............}. Lets say if have string like

{
      "type" : "id",
      "id" : ${idOf('/tar/check/inof/high1')},
      "details" : [
        {
          "name" : "Sanio",
          "sig" : "DA123QW"
        },
        {
          "name" : "Tarer",
          "sig" : "BAWE3QW"
        },
        {
          "name" : "Kadek",
          "sig" : "KSWE2J"
        },
      ]
    },

So i am searching for all patterns having ${whateverhere}

i am trying with

var pathRegExp = /\$(.*)\}/;

But it is not ending at "}" symbol.

i am searching for patterns like "${idOf('/tar/check/inof/high1')}" and wanted to encode them in double qoutes for JSON conversion... — gp apps
– gp apps, Commented Mar 4, 2015 at 20:40

Federico Piazza · Accepted Answer · 2015-03-04 20:47:28Z

2

Match pattern

If you want to match ${...} pattern then you can use this regex:

\$\{.*?\}

Working demo

enter image description here

Match pattern and grab content

On the other hand, if you want to capture the content within ${...} you can use capturing groups like this:

\$\{(.*?)\}
    ^---^--- Capture here

Working demo

enter image description here

The match information would be:

MATCH 1
1.  [38-67] `idOf('/tar/check/inof/high1')`
MATCH 2
1.  [199-209]   `anotherOne`

If you take a look at the Code generator section you can find the javascript code for this:

var re = /\$\{(.*?)\}/g; 
var str = '{\n      "type" : "id",\n      "id" : ${idOf(\'/tar/check/inof/high1\')},\n      "details" : [\n        {\n          "name" : "Sanio",\n          "sig" : "DA123QW"\n        },\n        {\n          "name" : "${anotherOne}",\n          "sig" : "BAWE3QW"\n        },\n        {\n          "name" : "Kadek",\n          "sig" : "KSWE2J"\n        },\n      ]\n    },';
var m;

while ((m = re.exec(str)) != null) {
    if (m.index === re.lastIndex) {
        re.lastIndex++;
    }
    // View your result using the m-variable.
    // eg m[0] etc.
}

edited Mar 4, 2015 at 20:47

answered Mar 4, 2015 at 20:41

Federico Piazza

31.2k15 gold badges91 silver badges133 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

gp apps Over a year ago

There could be multiple entries of "id". But this regular expression is not searching for all them...Any suggestions?

Federico Piazza Over a year ago

@gpapps you have to set the G (global) flag. I've just edited the answer

Ryen Nelsen · Accepted Answer · 2015-03-04 20:41:45Z

0

It sound's like you need to change it to something like this:

var pathRegExp = /\${(.*?)}/g;

Check it out here: Regex101

I made it become lazy, since Regex is greedy by default and was looking for the last } by default.

answered Mar 4, 2015 at 20:41

Ryen Nelsen

3871 silver badge9 bronze badges

Comments

Gabriel Pires · Accepted Answer · 2015-03-04 20:46:21Z

0

This is the regex you are looking for:

\$\{[^}]*\}

This way, it matches with the first ocurrence of '}', because [^}] means "match any character but '}'".

answered Mar 4, 2015 at 20:46

Gabriel Pires

3665 silver badges9 bronze badges

Comments

Rob · Accepted Answer · 2015-03-04 20:42:31Z

-1

You forgot the opening curly brace {

This should work:

/\$\{(.*)\}/

answered Mar 4, 2015 at 20:42

Rob

3151 silver badge9 bronze badges

Collectives™ on Stack Overflow

Reg Exp for string in Javascript

4 Answers 4

Match pattern

Match pattern and grab content

2 Comments

Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

4 Answers 4

Match pattern

Match pattern and grab content

2 Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related