Putting json content into PHP variable

Question

I need to manipulate some data which is being given to me in json format, from which I need to extract some data and put into a variable in PHP.

Having tried my best, I seem to end up with errors such as :

Use of undefined constant collectionViewUrl - assumed 'collectionViewUrl'

At the moment the only real code I have is this:

$string = file_get_contents("https://itunes.apple.com/search?term=rihanna+diamonds&country=gb&media=music&entity=musicTrack&attribute=musicTrackTerm&limit=1");
$json_result = json_decode($string, true);

I do not need an array of any kind, I just need to put the value of collectionViewUrl into a variable.

Somewhere you are referencing $collectionViewUrl without the $ sign — robbmj
– robbmj, Commented Mar 12, 2015 at 15:20
@robbmj is correct. Post the code where you reference collectionViewUrl. — Jason McCreary
– Jason McCreary, Commented Mar 12, 2015 at 15:22
This is what I was using echo $json_result[collectionViewUrl]; — omega1
– omega1, Commented Mar 12, 2015 at 15:26
The problem was that collectionViewUrl was not quoted $json_result["collectionViewUrl"]; also you were not looking in the correct array as noted in @Khaled Bentoumi answer. — robbmj
– robbmj, Commented Mar 12, 2015 at 15:29

BentoumiTech · Accepted Answer · 2015-03-12 15:33:12Z

2

Here how to get the collectionViewUrl string into a variable

$string = file_get_contents("https://itunes.apple.com/search?term=rihanna+diamonds&country=gb&media=music&entity=musicTrack&attribute=musicTrackTerm&limit=1");
$json_result = json_decode($string, true);
$collectionViewUrl = $json_result['results'][0]['collectionViewUrl'];

Here is a codepad where you can try the code http://codepad.org/6Zogs3si

Explanation :

When the 2nd parameter of json_decode is set to true the function return an associative array who's really close to the structure of the JSON.

From there all what you got to do is put back the JSON path into an associative php array to access the wanted value !

edited Mar 12, 2015 at 15:33

answered Mar 12, 2015 at 15:23

BentoumiTech

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2 Comments

omega1 Over a year ago

This works, many thanks for your assistance. marked as answer

BentoumiTech Over a year ago

@omega1 you're welcome happy to help, could you check it as answered so that it could help futur user ? Thanks

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