How do I replace all occurances of a value in a multidimensional php array?

Question

How would I replace any occurrence of value "FOO" with "BAR" in a nested/multidimensional php array? In my case, I'm trying to replace NAN (not a number) values with a string "NAN", but the same principles should apply. My incomplete example code:

function replaceNan($data)
{
    // probably some recursion here?
}

$data = [
    'foo' => NAN,
    'bar' => [
        'one' => 1,
        'nan' => NAN
    ],
    'baz' => 'BAZ'    
];

$data = replaceNan($data);
var_dump($data);

Unless there's a core php function that will help, I assume recursion will be involved, but I just can't figure it out right now. Any help appreciated.

Edit: Just to be clear, in my example, I would want $data to be modified so it looks like:

[
    'foo' => "NAN",
    'bar' => [
        'one' => 1,
        'nan' => "NAN"
    ],
    'baz' => 'BAZ'    
]

Can you just put your array format from which you want to remove something . Not whole but somehow, it help us to give you some solution because we don't know what is your array formt? — Death-is-the-real-truth
– Death-is-the-real-truth, Commented Mar 20, 2015 at 7:23

georg · Accepted Answer · 2015-03-20 08:19:52Z

1

How about

function replace_nan(&$ary) {
    foreach($ary as &$item) {
        if(is_double($item) && is_nan($item))
            $item = "NAN";
        else if(is_array($item))
            replace_nan($item);
    }
}

Array is passed by reference and modified in place:

$data = [...];
replace_nan($data);
var_dump($data);

edited Mar 20, 2015 at 8:19

answered Mar 20, 2015 at 7:19

georg

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3 Comments

Kevin Over a year ago

I think you need to return $ary, right? But this is definitely helpful.

georg Over a year ago

@Kevin: $ary is passed by reference and modified in place. No need to return it.

Kevin Over a year ago

Thanks! I missed that.

n-dru · Accepted Answer · 2015-03-20 07:37:44Z

0

This works for me:

 function replace_nan($a){
    foreach($a as $key1 => $array1){
         if(!is_array($array1)){
            if(!is_string($array1) && is_nan($array1)){
                $a[$key1] = "NAN";
            }
        }else{
            $a[$key1] = replace_nan($array1);
        }
    }
    return $a;
}

var_dump(replace_nan($data));

Yields:

array (size=3)
  'foo' => string 'NAN' (length=3)
  'bar' => 
    array (size=2)
      'one' => int 1
      'nan' => string 'NAN' (length=3)
  'baz' => string 'BAZ' (length=3)

edited Mar 20, 2015 at 7:37

answered Mar 20, 2015 at 7:30

n-dru

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