About Array Initialisation

Question

Can someone explain why i cannot use array={a,b}; :

public class Example {
 private final String a;
 private final String b;
 public final String[] array;

 public Example(){
  a="test";
  b="text";
  //String [] c = {a,b}; This is fine
  //array=c;
  array={a,b}; // this line throws an Exception
 }
}

Exception :

Exception in thread "main" java.lang.RuntimeException: Uncompilable source code - illegal start of expression
    at Example.<init>(Example.java:21)
    at hello.main(hello.java:26)
Java Result: 1

TheLostMind · Accepted Answer · 2015-04-02 06:30:25Z

4

Yes in case of initializing an array using {..}, the declaration and initialization should be done at the same time.

Well, marking array as final complicates things.. You will not be able to initialize it later (you will have to do it inside the constructor) . Your code will not compile.

Yes you could use : arr = new String[5]; in your constructor to initialize your array.

edited Apr 2, 2015 at 6:30

answered Apr 2, 2015 at 6:18

TheLostMind

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2 Comments

Zion Over a year ago

It is in the default constructor

TheLostMind Over a year ago

@CodeCat - Hadn't seen that.. My bad .. Edited my answer :).. Lashane's answer will work as well :)

Iłya Bursov · Accepted Answer · 2015-04-02 06:20:20Z

2

you should initialize array, like this:

array = new String[] {a,b};

answered Apr 2, 2015 at 6:20

Iłya Bursov

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