How to iterate over an array of objects without foreach and ArrayAccess

Question

I'm having to develop a site on PHP 5.1.6 and I've just come across a bug in my site which isn't happening on 5.2+. When using foreach() to iterate over an object, I get the following error: "Fatal error: Objects used as arrays in post/pre increment/decrement must return values by reference..."

Does anyone know how to convert the following foreach loop to a construct which will work with 5.1.6? Thanks in advance!

foreach ($post['commercial_brands'] as $brand)
                    {
                        $comm_food = new Commercial_food_Model;
                        $comm_food->brand = $brand;
                        $comm_food->feeding_type_id = $f_type->id;
                        $comm_food->save();
                    }

$post['commercial_brands'] is an object ?

Serty Oan
– Serty Oan

2010-06-02 14:51:27 +00:00
Commented Jun 2, 2010 at 14:51 — Serty Oan
– Serty Oan, Commented Jun 2, 2010 at 14:51

Joshua · Accepted Answer · 2010-06-02 14:53:09Z

1

Improving upon Coronatus's answer:

$max = count($post['commercial_brands']);
for ($i = 0; $i < $max; $i++)
{
    $comm_food = new Commercial_food_Model;
    $comm_food->brand = $post['commercial_brands'][$i];
    $comm_food->feeding_type_id = $f_type->id;
    $comm_food->save();
}

You should never have a function in the condition of a loop, because each time the loop goes around it will run the function.

answered Jun 2, 2010 at 14:53

Joshua

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2 Comments

Joshua Over a year ago

Actually, I'm right. It's well known that you need to determine the maximum number of times a for() should loop before the loop.

Joshua Over a year ago

It's why it's possible to change the number of entries in an array inside a for loop and still have it iterate through every one.

Satanicpuppy · Accepted Answer · 2010-06-02 14:54:35Z

1

$x = 0;
$length = count($post['commercial_brands']);
while($x < $length){
     $comm_food = new Commercial_food_Model;
     $comm_food->brand = $post['commercial_brands'][$x];
     $comm_food->feeding_type_id = $f_type->id;
     $comm_food->save();
     $x++;
}

//while 4 eva

answered Jun 2, 2010 at 14:54

Satanicpuppy

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Comments

Amy B · Accepted Answer · 2010-06-02 14:50:02Z

0

for ($i = 0; $i < count($post['commercial_brands']); $i++)
{
    $comm_food = new Commercial_food_Model;
    $comm_food->brand = $post['commercial_brands'][$i];
    $comm_food->feeding_type_id = $f_type->id;
    $comm_food->save();
}

answered Jun 2, 2010 at 14:50

Amy B

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1 Comment

kenny99 Over a year ago

Thanks Coronatus, not sure why i thought it would be more complicated than a good old fashioned for loop!

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