Building a PHP script to create new image

Question

I'm on my way to create a new script for my personal website. I want some kind of function where visitors can write something in an input field and then press generate image.

The script should then take a background image and insert the visitors text on top.

My question is: What is the php code to actually generate the image file and how do i connect the input data to the image?

I do not need full code examples if you don't have the time, i just need the basis practice of how to setup such a system.

php.net/manual/en/book.imagick.php imagemagick.org check your phpinfo() maybe u have it installed. Rest is self explanatory — animaacija
– animaacija, Commented Apr 17, 2015 at 9:46
Stackoverflow does not do your work. You should show at least minimal self effort in trying to solve your problem. — Sebastian Zartner
– Sebastian Zartner, Commented Apr 17, 2015 at 10:59
I feel my question is fairly within those borders. I only asked for the basic setup of such system. The gentlemen simply provided some code. — HereToHelpPHP
– HereToHelpPHP, Commented Apr 17, 2015 at 20:48

2kai · Accepted Answer · 2015-04-17 09:47:38Z

2

Try this code:

$filename = "layout.jpg";

$im = @imagecreatefromjpeg($filename);
$font = "tahoma.ttf";

$black = imagecolorallocate($im, 0, 0, 0);
$white = imagecolorallocate($im, 255, 255, 255);

imagettftext($im, 15, 0, 50, 50, $black, $font, $_POST['message_from_user']);

header('Content-Type: image/jpeg');

imagejpeg($im, null, 100);
imagedestroy($im);

layout.jpg is background image, tahoma.ttf is font file

Both files should be placed in the same folder.

This code would generate jpg-image with user string.

More details you would get by searching "gd in php".

answered Apr 17, 2015 at 9:47

2kai

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Comments

mohsenJsh · Accepted Answer · 2015-04-17 09:50:08Z

1

do something like this:

$text = 'put ur txt here'; 

$height = 25; 

$width = 65; 

$image_p = imagecreate($width, $height); 

$black = imagecolorallocate($image_p, 0, 0, 0); 

$white = imagecolorallocate($image_p, 255, 255, 255); 

$font_size = 14; 



imagestring($image_p, $font_size, 5, 5, $text, $white); 

imagejpeg($image_p, 'file name here', 80);

answered Apr 17, 2015 at 9:50

mohsenJsh

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