How to replace a string using regular expression?

Question

I am stuck at replacing a set of strings using bash. The strings looks like set18set18_nopep.fa. I want to replace the string with set18/set18_nopep.fa .The number can go from 1-9999 . So the number of digits is also variable.

Cyrus · Accepted Answer · 2015-04-21 05:04:22Z

3

echo set18set18_nopep.fa | sed 's|[0-9]\+|&/|'

Output:

set18/set18_nopep.fa

answered Apr 21, 2015 at 5:04

Cyrus

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John1024 · Accepted Answer · 2015-04-21 05:03:38Z

1

To put a slash between the end of the numbers and the word set:

$ s=set18set18_nopep.fa
$ echo "$s" | sed -r 's|([[:digit:]])set|\1/set|'
set18/set18_nopep.fa

To assign the new value to a string called t:

$ t=$(echo "$s" | sed -r 's|([[:digit:]])set|\1/set|')
$ echo "$t"
set18/set18_nopep.fa

answered Apr 21, 2015 at 5:03

John1024

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