I would like to display a popup message when user is logged out, so I use
echo "<script>alert(\"You are logged out\");</script>";
But it doesn't work.
Below is my coding. Is there any logic problem in my coding?
<?php
session_start();
if(isset($_SESSION['Username']) == "admin")
{
?>
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<style type="text/css">
@import "../CSS/Style.css";
@import "../CSS/Admin.css";
</style>
<title>Admin Home Page</title>
</head>
<body>
<div class="body"></div>
<?php
if(isset($_GET['id']) == "logout")
{
session_destroy();
echo "<script>alert(\"You are logged out\");</script>";
header("Location: ..\Main.php");
}
else
{
?>
<div class="menu">
<a href="ManageStaff.php">Manage Staff</a>
</div>
<div class="menu2">
<a href="ManageAccount.php">Manage Account</a>
</div>
<div class="logout">
<a href="AdminHomePage.php?id=logout">Logout</a>
</div>
<?php
}
}
else
{
?>
<center>
<p style="font-size:50px; font-weight:bold">Access Denied</p>
<p style="font-size:18px">Your request for this page has been denied because of access control</p>
</center>
<?php
}
?>
</body>
</html>
The session will be destroyed and will also redirect to Main.php, just the alert() will not come out.
isset()correctly [docs]. Secondly, you can't useheader()after output has been sent. Again, this is clearly stated in the php docs: php.net/manual/en/function.header.php. Finally, assuming you could, how do you expect your code to work? You can't mix PHP and Javascript; if you're using php to redirect the user, this would happen before anything is sent to the user, thus the javascript alert would never fire. You really need to think about your solution a bit more.issetwill only ever returntrueorfalse.