Search String with Arraylist in android

Question

in my android application i have tried to compare string with arraylist check it out my below code

ArrayList<String> namelist = new ArrayList<String>();
        ArrayList<String> withoutcomma = new ArrayList<String>();

        namelist.add("chennai , In");
        namelist.add("mumbai, In");
        namelist.add("Usak,TR");
        namelist.add("Ushuaia,AR");
        namelist.add("San Francisco,US");

        for (int i = 0; i < namelist.size(); i++) {
            String[] value = namelist.get(i).split("\\s*,\\s*");
            withoutcomma.add(value[0]);
            withoutcomma.add(value[1]);
        }

        String name = "i want to go chennai to mumbai";
        String[] splitname = name.split(" ");

        for (int i = 0; i < splitname.length; i++) {
            if (withoutcomma.contains(splitname[i])) {
                System.out.println(splitname[i]);
            }
        }

it returns correct output

chennai 
mumbai

but not able to get the value for san fransisco because white space, i am totally struck, even i have used Pattern and matches but not able to handle the white space

Can anybody help ??

Not possible with this scenario. Because you can not get San Francisco when split the name. — SANAT
– SANAT, Commented Jul 21, 2015 at 8:52

milez · Accepted Answer · 2015-07-21 08:26:33Z

2

Instead of splitting by white space, you could look for values of your withoutcomma array in the String name.

for (String str : withoutcomma)
{
    if (name.contains(str))
    {
        System.out.println("Found city: " + str + " at position: " + name.indexOf(str));
    }
}

And if the order of the cities matters, you can save the index of the value that was found in String name with int idx = name.indexOf(str).

answered Jul 21, 2015 at 8:26

milez

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8 Comments

Madhu Over a year ago

Thanks a lot it helps

Madhu Over a year ago

i am facing one more issue, when i use this code it returns all string which are all match with city ex: my arral list having both san fransico and san then this code return both san and san fransisco, where us i need only san fransisco

milez Over a year ago

You can use break; and continue; to control the for loop? Like add break; to the if-statement when you want to stop at first match?

Madhu Over a year ago

No i think it wont work because what's the solution if my required string is in end of the array, even i am not sure about my first match is the one i want, i need exact match, any idea

milez Over a year ago

I see now, can you add if-s for checking that the string is exactly the one you want?

|

Community · Accepted Answer · 2020-06-20 09:12:55Z

2

Split the words at commas as well as at any spaces. So, when ever you get a multiple word place name, store it in the Array, and then use it to compare. works for me.

Use this :

    ArrayList<String> namelist = new ArrayList<String>();
    ArrayList<String> withoutcomma = new ArrayList<String>();

    namelist.add("chennai , In");
    namelist.add("mumbai, In");
    namelist.add("Usak,TR");
    namelist.add("Ushuaia,AR");
    namelist.add("San Francisco,US");

    for (int i = 0; i < namelist.size(); i++) {
        String[] value = namelist.get(i).split("[(\\s*,\\s*)\\s]");
        for(String word : value) {
            withoutcomma.add(word);
        }
    }

    String name = "i want to go San Francisco to mumbai";
    String[] splitname = name.split(" ");

    for (int i = 0; i < splitname.length; i++) {
        if (withoutcomma.contains(splitname[i])) {
            System.out.println(splitname[i]);
        }
    }

edited Jun 20, 2020 at 9:12

CommunityBot

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answered Jul 21, 2015 at 8:52

Samrat Dutta

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1 Comment

Madhu Over a year ago

No it gives me separated output

Elmira Frhn · Accepted Answer · 2015-07-21 08:26:52Z

1

you can use trim() to omit space in San Francisco,

change

 String[] value = namelist.get(i).split("\\s*,\\s*");

to

 String[] value = namelist.get(i).trim().split("\\s*,\\s*");

answered Jul 21, 2015 at 8:26

Elmira Frhn

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