Level Array in Java

Question

I have recently migrated from JS and the Processing library to LibGDX with Java. In my time with JS, I have used code like this, for level design:

var level = [
    " aaaaaaaaa",
    " aaaaaaaaa",
    " aaaaaaaaa",
    " aaaaaaaaa",
    " aaaaaaaaa",
    "aaaaaaaaaa",
    "aaaaaaaaaa",
    "saaaggaaaa",
    "ggggccgggg",
    "cccccccccc",
    "aaaaaaaaaa",
    "aaaaaaaaaa",
    "cccccccccc"
];

With this, I made a for loop and switch like so:

for(var c = 0; c < level.length; c ++){ 
    for(var r = 0; r < level[c].length; r ++){
        switch(level[c][r]) {
            case 'a':
                rect(r*40, c*40, 40, 40);
                break;
            case 'g':
                ...
        }
    }
}

This checks through each character in each string in the array. Due to Java's more abstract system of variables and lack of interchangeable array and string properties, I have found it very difficult to do this same thing in Java. Does anyone know of a way that I can? Thanks in advance!

I had loaded my "Java is not Javascript" gun but this time it's actually a question about both languages :D — Dici
– Dici, Commented Aug 6, 2015 at 0:05
By the way Java, as a language, is much better than Javascript and it does not lack anything JS could ever have. JS is a terrible language which happens to be the most used so people came up with lots of librairies which make it less terrible... but it is still a deeply flawed language.Be happy for having migrated — Dici
– Dici, Commented Aug 6, 2015 at 0:09
@Dici last time I tried Java in a web browser it had some serious problems :) — Pointy
– Pointy, Commented Aug 6, 2015 at 0:17
@Dici, Pointy, Nayuki-Minase: This thread is now officially a JavaScript-bashing thread. All further comments on this post that do not involve criticism of JavaScript will be considered off-topic as will be promptly removed as such. /s — Maximillian Laumeister
– Maximillian Laumeister, Commented Aug 6, 2015 at 2:01

Paul Boddington · Accepted Answer · 2015-08-06 00:00:15Z

4

It's very similar in Java.

String[] level = {
            " aaaaaaaaa",
            " aaaaaaaaa",
            " aaaaaaaaa",
            " aaaaaaaaa",
            " aaaaaaaaa",
            "aaaaaaaaaa",
            "aaaaaaaaaa",
            "saaaggaaaa",
            "ggggccgggg",
            "cccccccccc",
            "aaaaaaaaaa",
            "aaaaaaaaaa",
            "cccccccccc"
};
for(int c = 0; c < level.length; c ++){
    for(int r = 0; r < level[c].length(); r ++){
        switch(level[c].charAt(r)) {
            case 'a':
                // do something    
                break;
            case 'g':
                // etc   
        }
    }
}

answered Aug 6, 2015 at 0:00

Paul Boddington

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2 Comments

Shivashriganesh Mahato Over a year ago

Works perfectly! Thanks so much! :D

Shivashriganesh Mahato Over a year ago

Can you help me again? I am wondering how to append a new instance of a certain class to an array that is meant to hold those instances in place of // do something, and then call the appropriate methods by looping through the array. Do you get what I'm trying to do? Thanks in advance!

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