Conditional regex php

Question

I'm facing some problem with php regex but after many researches (conditional regex, subpattern regex), I still can't solve it.

I have a folder that contains many images and based on variable value I have to go to that folder and select all images that match the value. e.g: In my folder I have 3 images:

p102.jpg ; p1020.jpg ; p102_1.jpg;

I only want the regex to select :

p102.jpg ; p102_1.jpg

but with the regex below It selects all 3 images.

$image_to_find = 102;
$path = "[^\d]*.*/"
$test = "/^[a-zA-Z]?$image_to_find".$path;
foreach(glob($file_directory) as $file){
 if(preg_match($test, $file)){
   match[]= $file;
 }
}

I also try:

$path = "(?:\_[0-9]?).*/"; (it selects only p102_1.jpg)

Can you help me to figure it out. thanks (sorry for the english)

Why do you want it to select those two images, what is the rule that you are trying to build. — Rahul Kadukar
– Rahul Kadukar, Commented Sep 11, 2015 at 16:28
@Casimir the letter doesn't appear always. mayo code is working. I also replace $path="[^\d]*.*/" by $path="[^\d]/" and it working. Thanks for your help — John
– John, Commented Sep 11, 2015 at 16:50

Casimir et Hippolyte · Accepted Answer · 2015-09-11 17:17:03Z

2

You can avoid the foreach loop if you use the glob pattern:

$num = 102;

$result = glob($path . '[a-zA-Z]' . $num . '[._]*');

Note: if you need to allow several different formats, you can use array_merge and several glob patterns: array_merge(glob(...), glob(...));

If you want the first letter optional:

$result = array_merge(
    glob($path . $num . '[._]*jpg'),
    glob($path . '[a-zA-Z]' . $num . '[._]*jpg')
);

or better, use the brace option:

$result = glob($path . '{[a-zA-Z],}' . $num . '[._]*jpg', GLOB_BRACE);

That stays a better alternative than the combo "foreach/preg_match" (or preg_grep) if filenames are not too complicated.

With preg_grep:

$pattern = '~(?:^|/)[a-z]?' . $num . '(?:_\d+)?\.jpg$~i';
$result = preg_grep($pattern, glob($path . '*' . $num . '*.jpg'));

edited Sep 11, 2015 at 17:17

answered Sep 11, 2015 at 16:44

Casimir et Hippolyte

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Comments

mayo · Accepted Answer · 2015-09-11 16:30:57Z

1

Try this:

/p102[_\.]\d*\.?jpg/g

https://regex101.com/r/hM4oE0/1

Where p102 should be your 'image_to_find' var.

answered Sep 11, 2015 at 16:30

mayo

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1 Comment

DeDee Over a year ago

Yup, I came up with something similar but you were faster. I tested yours and it works.

Ido · Accepted Answer · 2015-09-11 16:37:02Z

0

Not tested, should work.

$find = 102;
$pattern = "/p". $find ."(?:_\d+)?\.jpg/";
$list = array();

foreach (glob($file_directory) as $file)
{
    if (preg_match($pattern, $file))
    {
        $list[] = $file;
    }
}

regex: http://regexr.com/3bp29

answered Sep 11, 2015 at 16:37

Ido

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Comments

Allan Andrade · Accepted Answer · 2015-09-11 17:14:37Z

-1

Tested and working:

<?php
$image_to_find = 102;
$pattern = '[a-zA-Z]' . $image_to_find . '[._]*';
$path = '/your_folder/your_subfolder/';
$file_directory = glob($path . $pattern );
echo '<pre>';
var_dump($file_directory);
echo '</pre>';
exit();

I hope this helps!

edited Sep 11, 2015 at 17:14

answered Sep 11, 2015 at 16:44

Allan Andrade

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