Display Loop from Database correctly Python

Question

i would Like to display the word 'conflict' if the value is more than one in the list. this is my code

list = ['aa','bb','cc','aa']

conf = [s for s in list]

for a in list:
    if len(a in conf) > 1:
        print a, "-conflict"
    else:
        print a

I think my syntax is wrong in if len(a in conf)> 1: Please help me.

I am expecting this result:

aa - conflict
bb
cc
aa - conflict

Prajwal K R · Accepted Answer · 2015-09-30 05:04:43Z

1

You can use the count function.

if conf.count(a) > 1:
    print a, "-conflict"

The above method is similar to what you have tried. But this is inefficient when the list is large. So, use collections.Counter.

from collections import Counter
occurences = Counter(conf)
for a in list:
    if occurences[a] > 1:
        print a, "- conflict"
    else:
        print a

edited Sep 30, 2015 at 5:04

Prajwal K R

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answered Sep 30, 2015 at 3:52

Aswin Murugesh

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2 Comments

James Reid Over a year ago

Hi thanks.... I just want to ask because I will put this codes in html. it worked in shell however when I put this in my template. I got error. {% if conf.count(a) > 1%}. and it would show an error message "Could not parse the remainder"

Aswin Murugesh Over a year ago

@FredGarcia stackoverflow.com/questions/2468804/…

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