Regular Expression to replace part of a string

Question

I need to replace part of a string, it's dynamically generated so I'm never going to know what the string is.

Here's an example "session12_2" I need to replace the 2 at the end with a variable. The "session" text will always be the same but the number will change.

I've tried a standard replace but that didn't work (I didn't think it would).

Here's what I tried:

col1 = col1.replace('_'+oldnumber+'"', '_'+rowparts[2]+'"');

Edit: I'm looking for a reg ex that will replace '_'+oldnumber when it's found as part of a string.

@raina77ow could you give me a bit more info on how that would work please? — flyersun
– flyersun, Commented Oct 7, 2015 at 13:37

Aleksei Golubev · Accepted Answer · 2015-10-07 13:47:10Z

4

If you will always have the "_" (underscore) as a divider you can do this:

 str = str.split("_")[0]+"_"+rowparts[x];

This way you split the string using the underscore and then complete it with what you like, no regex needed.

edited Oct 7, 2015 at 13:47

Aleksei Golubev

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answered Oct 7, 2015 at 13:38

André Ferrari

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3 Comments

Markai Over a year ago

Just a little typo: You would actually be splitting the string, not the screen ;)

Roko C. Buljan Over a year ago

Or in translation: col1 = col1.split('_')[0] +"_"+ rowparts[2];

André Ferrari Over a year ago

Thanks Markai. And Roko too. That is more like the question.

Māris Kiseļovs · Accepted Answer · 2015-10-07 13:39:52Z

0

var re = /session(\d+)_(\d+)/; 
var str = 'session12_2';
var subst = 'session$1_'+rowparts[2]; 

var result = str.replace(re, subst);

Test: https://regex101.com/r/sH8gK8/1

answered Oct 7, 2015 at 13:39

Māris Kiseļovs

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1 Comment

Roko C. Buljan Over a year ago

there's no need to use a Capture group before the _

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