Printing bit patterns

Question

So I am to be making a "bit pattern that will have 7 rows. I am having trouble drawing any letters with 1's and 0's while I can only use if or else statements, parse.Int, and compareTo as the instructions say. The program needs to change every 1 to an "X" and every 0 to a space. Is there a specific way to do this? For now it just endlessly loops. Thanks for any and all help. Here is my code thus far:

public static void main(String[] args) 
{
    String r1 = ("1, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0");
    String r2 = ("0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0");
    String r3 = ("0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0");
    String r4 = ("0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0");
    String r5 = ("0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0");
    String r6 = ("0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0");
    String r7 = ("0, 0, 1, 0, 0, 0, 0, 1, 1, 1, 1, 0, 0, 0, 1, 0, 1, 0, 0");

    dr(r1);
    dr(r2);
    dr(r3);
    dr(r4);
    dr(r5);
    dr(r6);
    dr(r7);
}
public static void dr(String s)
{
    int i = 0;
    while(i < 1)
    {
    String[] tokens = s.split(" ");
    if (tokens[0].compareTo("0") == 0)
        System.out.println("X");
    else if (tokens[1].compareTo("1") == 1)
        System.out.println(" ");
    }
}

why do you need any special libraries for printing 0's and 1's?? — Swastik Padhi
– Swastik Padhi, Commented Oct 25, 2015 at 1:52
@CrakC I dont need special libraries for that. I am to be creating a bit pattern that basically draws whatever letters I put with 1's and 0's. — NaughtyBear
– NaughtyBear, Commented Oct 25, 2015 at 1:53
The rows will be locked at 7. But no the columns are not locked. They are only "locked" by whatever letter I may type in. — NaughtyBear
– NaughtyBear, Commented Oct 26, 2015 at 7:27

bezmax · Accepted Answer · 2015-10-26 07:29:32Z

1

The easiest way to do it in your case is something like this:

String data = "1, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0";
String out = data.replaceAll("1,? ?","X").replaceAll("0,? ?", " "));

answered Oct 26, 2015 at 7:29

bezmax

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3 Comments

NaughtyBear Over a year ago

That is certainly an awesome way! But I am unable to use any specialized library.

bezmax Over a year ago

Specialized? replaceAll is part of String class with no additional libraries.

NaughtyBear Over a year ago

Sorry, I misspoke. What I was meaning is we are not allowed to use elements we have not gone over. He has yet to go over those elements, thus why I am in a predicament. The compare to and if/else statements are the only way we can do this program. It is unfortunate, but such as the way of things.

Lezorical · Accepted Answer · 2015-10-25 01:55:59Z

0

I will suggest that you assign each letter a value (Your bits), and then storing them in an array...

We need the code.

answered Oct 25, 2015 at 1:55

Lezorical

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2 Comments

NaughtyBear Over a year ago

Thank you for your suggestion! I would post the code, but so far all I have is the array set and a method to pass a function through. But the problem I am fighting with is actually drawing with 1's and 0's as the logic has to be set. So no matter what letters I put in, it needs to draw at least 3 letters.

Swastik Padhi Over a year ago

atleast 3 letters? why so??

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