Generator-based coroutines can be easily created from function object:
coro = asyncio.coroutine(func)
What about native coroutines (which usually creates by async def)?
Is there any way to create them from existing function objects?
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1 Answer
In Python 3.5 the way to create an async function is by using the async def() syntax. Not sure of the benefit of trying to wrap a normal function into a native coroutine because if there is nothing to await, it would seem pointless? Especially since there is no need to call the function using await or yield from? (Since you can just execute it normally.)
Nevertheless, would this work for your purposes?
def test():
print('boo')
async def async_test():
return test()
5 Comments
Mikhail Gerasimov
Benefit to wrap in special cases, when we can't define function as coroutine, but we need to use it as coroutine. Better to see: stackoverflow.com/a/23036785/1113207
songololo
Do you have a specific example of a use case?
Andrew Svetlov
I don't follow the use case also.
Mikhail Gerasimov
You're right. I just understood, I really don't need it.
Randelung
For the record, I have a use case. I have a rogue task creation somewhere I want to find, so I'd like to wrap the existing code in a coroutine and return that from a normal function, which would then allow me to call
traceback.print_stack() before returning the coroutine. asyncio.coroutine(func) worked, though. Just... you have to convert every await inside the function or comment them out.